Answer:
20x^6
Step-by-step explanation:
multiply bases and add exponents
Answer:
Step-by-step explanation:
<u>Area formula</u>
<u>Applied to the given rectangle, we have</u>
<u>Since 36 ≤ A ≤ 72, substituting A</u>
It is viable.
X² - 169 = 0
x = ?
<span> Add 169 to both sides.
</span>
x² <span>− 169 + 169 </span>= <span>0 + 169</span>x² = 169
Square root
x = <span>± <span>√<span>169
</span></span></span>
<span><span>x = <span><span>13<span> or </span></span>x </span></span>= <span>−13
x can be 13 or -13.</span></span>
Answer:

Step-by-step explanation:
If G is the midpoint of CD, and AC is parallel to DB, then AC = DH.
Therefore, G is the midpoint of AH and ΔACE is similar to ΔDBE.
As AC : DB = 1 : 3
⇒ Area of ΔACE : Area of ΔDBE = 1² : 3² = 1 : 9
We are told that Area ΔACE = Area ΔAEG.
⇒ Area ΔACG = 2 × Area ΔACE
As AC = DH, and G is the midpoint of CD:
⇒ ΔACG ≅ ΔHDG
⇒ Area ΔHDG = 2 × Area ΔACE
Area of quadrilateral EGHB = Area of ΔDBE - Area ΔHDG
= Area of ΔDBE - 2 × Area of ΔACE
Therefore:


Using the ratio of Area ΔACE : Area ΔDBE = 1 : 9

