Question 1)
Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x
F(G(x)) = 3(2x - 3)^2 + 1
F(G(x)) =3(4x^2 - 12x + 9) + 1
F(G(x)) = 12x^2 - 36x + 27 + 1
F(G(x)) =12x^2 - 36x + 28
Question 2)
Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x
H -1 (x) = x (inverse)
Answer: Move terms to the left side−52+3=−9−5x2+3x=−9−52+3−(−9)=0−
Common factor−52+3+9=0−5x2+3x+9=0−(52−3−9)=0
Divide both sides by the same factor−(52−3−9)=0−(5x2−3x−9)=052−3−9=0
Solution=3±321 over 10
Step-by-step explanation:
Answer:
6x +19
Step-by-step explanation:
6(x +2) +7
distribute the 6 (multiply 6*x and 6*2)
6x + 12
add the 7 to the 12
=6x + 19
Answer: 7 years
Step-by-step explanation:
= In2 / ∧
since the half life is given , we have :
22 = In 2/ ∧
∧ = In2/22
∧ = 0.032
Recall the formula for half life:
= 
Therefore:
0.80 = 
Take the In of both sides
In 0.80 = - 0.032t
t = In 0.80 / - 0.032
t = 7 years
