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raketka [301]
2 years ago
11

Which list shows the numbers below in order from least to greatest?

Mathematics
1 answer:
goldfiish [28.3K]2 years ago
7 0

Answer:

<h2>\frac{\pi }{5} , 1.6%, -2\frac{4}{5}, -2\sqrt{2}</h2>

Step-by-step explanation:

I plugged in the values to a calculator

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Solve this equation 1 = 1 - 2n + 8
dolphi86 [110]
<h3>Answer:</h3>

n=4

<h3>Explanation:</h3>

1 = 1 - 2n + 8

2n =  - 1  + 1 + 8

2n = 8

n = 4

I hope you are satisfied

5 0
3 years ago
For what values of m does the graph of y = mx?- 5x-2 have no<br>5x - 2 have no x-intercepts?​
Rasek [7]

Answer:

no

Step-by-step explanation:

It does.

5x-2=0

5x=2

x=2/5

(2/5, 0)

is an x-intercept

6 0
3 years ago
Read 2 more answers
DJ Mykel is making a playlist for a radio show; he is trying to decide what 14 songs to play and in what order they should be pl
konstantin123 [22]

Answer:

5878600 different playlists.

Step-by-step explanation:

Since we require 14 songs for the playlist and there are 7 hip-hop, 5 jazz, 7 pop, and 8 blues songs, and DJ Mykel wants to play no more than 3 hip-hop songs, the number of ways in which he can combine the 7 hip-hop songs to play no more than 3 is ⁷C₃ = 7!/4!3!.

Now, since we have 3 songs already selected, we are left with 14 - 3 = 11 songs to select.

Since we have selected the 3 hip-hop songs, we are left with 5 jazz, 7 pop, and 8 blues songs which sum to a total of 20 songs.

So, we have 20 songs to select in 11 ways which is ²⁰C₁₁ = 20!/(20 - 11)!11! = 20!/9!11!

So, the number of different playlists that can be formed is thus

⁷C₃ × ²⁰C₁₁ =  7!/4!3!.× 20!/9!11!

= 35 ×  167960

= 5878600 different playlists.

8 0
2 years ago
If 4% of x equals 56, what is x
Gekata [30.6K]
X is = 1400. That's the answer
4 0
3 years ago
Assuming that the population is normally​ distributed, construct a 9090​% confidence interval for the population mean for each o
jasenka [17]

Given:

Set A: 1 4 4 4 5 5 5 8

Mean: 4.5

Standard dev: 1.9

 

Set B:

Mean: 4.5

Standard dev: 2.45

 

% =  90 

Set A:

Standard Error, SE = s/ √n =    1.9/√8 = 0.67  

Degrees of freedom = n - 1 =   8 -1 =  7   

t- score =  1.89457861

<span> <span><span> <span>   </span> </span> </span></span>

Width of the confidence interval = t * SE =     1.89457861* 0.67 = 1.272685913

Lower Limit of the confidence interval = x-bar - width =      4.5 - 1.272685913 = 3.23

Upper Limit of the confidence interval = x-bar + width =      4.5 + 1.272685913 = 5.77

The 90% confidence interval is [3.23, 5.77]

 

Set B:

Standard Error, SE = s/ √n =    2.45/√8 = 0.87  

Degrees of freedom = n - 1 =   8 -1 = 7   

t- Score =  1.89457861

<span> <span><span> <span>   </span> </span> </span></span>

Width of the confidence interval = t * SE =     1.89457861* 0.87 = 1.641094994

Lower Limit of the confidence interval = x-bar - width =      4.5 - 1.641094994 = 2.86

Upper Limit of the confidence interval = x-bar + width =      4.5 + 1.641094994 = 6.14

The 90% confidence interval is [2.86, 6.14]

 

<span>We can obviously see that sample B has more variation in the scores than sample A. The fact that the standard deviation is 2.45 for B and 1.9 for A). Therefore, they yield dissimilar confidence intervals even though they have the same mean and range.</span>

6 0
3 years ago
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