Triangles ABD and BCD are similar, because they are both right and share a common angle, and thus all three angles are equal.
This means that we can set the proportion
Plug the numbers and we have
Solve for 
:
Answer:
10x² - 48y² - 11x + 2y - 74xy
Step-by-step explanation:
(-x+8y)+(-10x-6y)(−x+8y)+(−10x−6y)
Rearranging,
=> - x - 10 x + 8y - 6y + (-10x-6y)(−x+8y)
=> - 11x + 2y + 10x² - 48y² + 6xy - 80xy
=> 10x² - 48y² - 11x + 2y - 74xy
Answer:
isweartogodiwillcomment
Step-by-step explanation:
Answer:
Step-by-step explanation:
![We\ are\ given\ that,\\Line\ YZ\ ||\ ZW\\\angle XYM=90\\Hence,\\Line\ Segment\ XY\ being\ the\ transversal,\ cuts\ YZ\ and\ XW.\\Hence,\\We\ know\ that\\The\ set\ of\ co-interior\ angles [Interior\ angles\ on\ the\ same\ side\\ of the\ transversal]\ are\ supplementary.\\Hence,\\Here,\\The\ pair\ of\ co-interior\ angles\ formed\ are\ \angle XYZ\ and\ \angle YXW.\\Hence,\ they\ are\ supplementary\ too.\\Hence,\\\angle XYZ\ + \angle YXW= 180\\Hence, by\ substituting\ XYZ=90+2x,\angle YXW=3x-5](https://tex.z-dn.net/?f=We%5C%20are%5C%20given%5C%20that%2C%5C%5CLine%5C%20YZ%5C%20%7C%7C%5C%20ZW%5C%5C%5Cangle%20XYM%3D90%5C%5CHence%2C%5C%5CLine%5C%20Segment%5C%20XY%5C%20being%5C%20the%5C%20transversal%2C%5C%20cuts%5C%20YZ%5C%20and%5C%20XW.%5C%5CHence%2C%5C%5CWe%5C%20know%5C%20that%5C%5CThe%5C%20set%5C%20of%5C%20co-interior%5C%20angles%20%5BInterior%5C%20angles%5C%20on%5C%20the%5C%20same%5C%20side%5C%5C%20of%20the%5C%20transversal%5D%5C%20%20are%5C%20supplementary.%5C%5CHence%2C%5C%5CHere%2C%5C%5CThe%5C%20pair%5C%20of%5C%20co-interior%5C%20angles%5C%20formed%5C%20are%5C%20%5Cangle%20XYZ%5C%20and%5C%20%5Cangle%20YXW.%5C%5CHence%2C%5C%20they%5C%20are%5C%20supplementary%5C%20too.%5C%5CHence%2C%5C%5C%5Cangle%20XYZ%5C%20%2B%20%5Cangle%20YXW%3D%20180%5C%5CHence%2C%20by%5C%20substituting%5C%20XYZ%3D90%2B2x%2C%5Cangle%20YXW%3D3x-5)
Answer:
53&8
Step-by-step explanation:
38-23=15
23+15+15=53
23-15=8
