If a triangle has vertices A (-5, 1), B (3, 5) and C (2, -3),

Mathematics

1 answer:

elixir [45]3 years ago

8 0

Answer:

Step-by-step explanation:

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Which equation represents the line shown on the coordinate grid below?

kondor19780726 [428]

I thinks it’s A or C )) but it’s not b or d, I’m pretty sure. So imma go with A or c

5 0

2 years ago

Simplify: -3^2+8÷2×4-|-9|

NNADVOKAT [17]

Follow the order of operations. Evaluate absolute value first.
-3^2+8/2*4-9

Then evaluate exponents
9+8/2*4-9

Then evaluate multiplication and division from left to right
9+4*4-9
9+16-9

Then evaluate addition and subtraction from left to right
25-9
16

Final answer: 16

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3 years ago

You roll a fair six sided die twice. The first roll shows a six and the second row shows 3

vazorg [7]

Answer:

4/12 simplified to 1/3 of rolling 2 times.

Step-by-step explanation:

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2 years ago

Solve by using square root: <br> 4(x-1)^2+2=10

Scilla [17]

$4(x-1)^2+2=10\\\\4(x^2-2x+1)+2-10=0\\\\4 x^2-8x+4+2-10=0\\\\4 x^2-8x-4=0\ \ / :4\\\\x^2-2x-1=0\\\\x_{1}=\frac{-b-\sqrt{b^2-4ac}}{2a}=\frac{2-\sqrt{ (-2)^2-4*1*(-1)}}{2 }=\frac{2-\sqrt{ 8}}{2 }=\frac{2- \sqrt{ 4*2}}{2 }=\\\\=\frac{2-\sqrt{ 8}}{2 }=\frac{2(1- \sqrt{ 2})}{2 }=1- \sqrt{ 2}\\\\x_{2}=\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{2+\sqrt{ (-2)^2-4*1*(-1)}}{2 }=\frac{2(1+ \sqrt{ 2})}{2 }=1+ \sqrt{ 2}$

$Answer:\ x=1- \sqrt{2}\ \ or\ \ x= 1+ \sqrt{ 2}$

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3 years ago

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Which are vertical angles? Check all that apply. ∠EAB and ∠BAC ∠EAB and ∠CAD ∠CAD and ∠FAE ∠CAB and ∠DAE ∠DAC and ∠DAE

Anastaziya [24]

Answer:

<CAB and <DAE are vertical angles

<EAB and <CAD are vertical angles

Step-by-step explanation:

this is because they are formed by the prolongation of the sides of the other angles and are opposite to them on the other side of the vertex.

8 0

3 years ago

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