Answer: D) 13y^25 and 2y^25
Like terms involve the same variables, and each of those variables must have the same exponents.
Another example of a pair of like terms would be 5x^3y^2 and 7x^3y^2. Both involve the variable portion "x^3y^2" which we can replace with another variable, say the variable z. That means 5x^3y^2 becomes 5z and 7x^3y^2 becomes 7z. After getting to 5z and 7z, it becomes more clear we have like terms.
r-12
substitute in r=7
so 7-12 = -5
Write the coeeficientes of the polynomial in order:
| 1 - 5 6 - 30
|
|
|
------------------------
After some trials you probe with 5
| 1 - 5 6 - 30
|
|
5 | 5 0 30
-----------------------------
1 0 6 0 <---- residue
Given that the residue is 0, 5 is a root.
The quotient is x^2 + 6 = 0, which does not have a real root.
Therefore, 5 is the only root. You can prove it by solving the polynomial x^2 + 6 = 0.
Answer:
<u>Given</u>
- tanθ = 3.454
- θ is in the III quadrant
We know in the III quadrant both sine and cosine are negative.
<u>Use the following identities to get values of sinθ and cos θ</u>
- sinθ = - tanθ/√(1 +tan²θ)
- cosθ = - 1/√(1 +tan²θ)
<u>Substitute the value of tanθ and find sine and cosine:</u>
- sinθ = - 3.454/√(1 + 3.454²) = - 0.961
- cosθ = - 1/√(1 + 3.454²) = - 0.278
Answer:
Well, if the grip is 75 x 75, you can rule out that the grid is 75 squares in each border.
Step-by-step explanation:
75 x 75 = a x b
a= horizontal side lengths
b= vertical side lengths
Rule that a= 75 squares and b= 75 squares.
