Given that the roots of the equation x^2-6x+c=0 are 3+8i and 3-8i, the value of c can be obtained as follows;
taking x=3+8i and substituting it in our equation we get:
(3+8i)^2-6(3+8i)+c=0
-55+48i-18-48i+c=0
collecting the like terms we get:
-55-18+48i-48i+c=0
-73+c=0
c=73
the answer is c=73
Multiple values of y for a single value of x is a sure giveaway that this is NOT a function. Please review definitions of "function." A function would be represented if no x value has more than one y value associated with it.
The only that has the shape of the one below.
y = -4(x^3 + 7x^2+8x - 16)
Let x = 1
y = - 4(1 + 7 + 8 - 16)
y = 0
y = -4(x -1)(x^2 + 8x + 16)
y = -4(x - 1)(x + 4)^2
2 1/4 times 3 1/9
Make the fractions into decimals
So now it’s 2.25 times 3.11...
Multiply that to get 6.99 but since the 3.11... is a repeated sequence you would round it to 7, which is your answer!
Equation
10x1/2+(-6) (-3)
Answer
23