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slavikrds [6]
3 years ago
6

What is Janelle’s position relative to sea level while swimming? What should the altimeter read at this position?

Mathematics
2 answers:
skelet666 [1.2K]3 years ago
5 0

Answer:

Janelle's position on the Altimeter should read -1/2

Step-by-step explanation:

the reason it reads -1/2 is because she is a  below sea level

kondor19780726 [428]3 years ago
4 0

Answer: Janelle is 1/2 below sea level, the altimeter should read -1/2 feet

Step-by-step explanation:

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Answer:

  • \mathrm{Domain\:of\:}\:-5x-1\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

  • \mathrm{Range\:of\:}-5x-1:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

Step-by-step explanation:

Finding the domain:

The domain of a function is the set of possible input values for which the function is real and defined.

Given the function

y=-5x-1

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-\infty \:

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\mathrm{Domain\:of\:}\:-5x-1\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

Finding the range:

The range of a function is the set of possible output values (dependent variable y values) for which a function is defined.

The range of polynomials with odd degree is all the real numbers.

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-\infty \:

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\mathrm{Range\:of\:}-5x-1:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

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3 years ago
In 2003 a town’s population was 1431. By 2007 the population had grown to 2134. Assume the population is changing linearly.How m
sergiy2304 [10]

We will have the following:

First, we will have that the population change by:

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So, the population changed by 703 people.

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So, it took 4 years to changes from 1431 to 2134.

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The average population growth per year is of 175.75 people per year.

The population in 2000 would have been:

P_{2000}=\frac{2000\cdot1431}{2003}\Rightarrow P_{2000}=1428.856715\ldots

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We will have that the equation for the population would be:

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Now, we predict the number of people of the town in 2014:

P_{2014}=175.75(14)+1429\Rightarrow P_{2014}=3889.5

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So, there will be approximately 3890 people of the town in 2014.

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