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alisha [4.7K]
3 years ago
13

Use the laws of Sines and law of cosines to find missing Dimensions. Part 2​

Mathematics
2 answers:
Usimov [2.4K]3 years ago
7 0

9514 1404 393

Answer:

  13.  (A, b, C) = (30.66°, 91.042, 25.34°)

  14.  insufficient information

Step-by-step explanation:

13. The Law of Cosines can help you find the side opposite the given angle. Then that can be used with the Law of Sines to find the other angles.

  b = √(a² +c² -2ac·cos(B)) = √(56² +47² -2(56)(47)cos(124°)) ≈ √8288.59

  b ≈ 91.042

__

  A = arcsin(a/b·sin(B)) ≈ arcsin(56/91.042·sin(124°)) ≈ 30.66°

  C = 180° -124° -30.66° = 25.34°

The missing dimensions are (A, b, C) = (30.66°, 91.042, 25.34°).

__

14. One side and one angle do not define a unique triangle. There is insufficient information to find f.

Alexxandr [17]3 years ago
5 0
The person above me answered the question!



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What is the inverse of function f? A) B) C) D)<br> Plato
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(7x-3)/-1

Step-by-step explanation:

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In adjoining figure a circle is inscribed in the quadrilateral ABCD given that BC is equal to 38 cm cube is equal to 27 cm and B
lukranit [14]

<h3>Radius = 14cm</h3>

Step-by-step explanation:

Let O be the centre of the circle. Since P and S are the points of contact of tangents AD and DC respectively, OP ⊥ AD and OS ⊥ DC

Also, AD ⊥ DC (given), therefore, OPDS is a square.

BR = BQ = 27cm...(tangents from an external point to a circle are equal in length)

therefore, CR = CB - BR = (38 - 27)cm = 11cm

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5 0
2 years ago
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If I have 7 button down shirts, 5 pairs of pants and 3 pairs of shoes that I can wear to work then how many different outfits ca
34kurt

105 different outfits can wear on an individual day

<em><u>Solution:</u></em>

I have 7 button down shirts, 5 pairs of pants and 3 pairs of shoes that I can wear to work

To find: Number of different outfits can I wear on an individual day

First he has to decide on a pair of pants and he has 5 different choices

For each of those choices he has a choice of 7 different button down shirts, so that gives him 5 x 7 = 35 different pant/shirt combinations

For each of those 35 different pant/shirt combinations, he has 3 pairs of shoes he could select, so altogether he has 35 x 3 = 105 different outfits

In short we can say,

different outfits = 7 x 5 x 3 = 105

So there 105 different outfits can wear on an individual day

4 0
3 years ago
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