Every positive real number has TWO<span>square roots; One is positive and one is negative. They are opposites of each other. </span>
10 is a square root of 100 because (10)(10) = 100, and ̶ 10 is also a square root of 100 because ( ̶ 10)( ̶ 10) = 100.
In general, “a” is a square root of “b” if a² = b, where “a” is a real number and b ≥ 0.
In conclusion:
<span> √(100) = </span>10<span> (the </span>positive<span> square root of 100) </span>and<span> </span>
<span> ̶ √(100) = ̶ (10) = </span>̶ 10<span> (the </span>negative<span> square root of 100)</span>
Answer:
Step-by-step explanation:
Mark as brainliest
Answer:
C.
Step-by-step explanation:
p(x)=sin(x) is an odd function since sin(-x)=-sin(x).
q(x)=cos(x) is an even function since cos(-x)=cos(x).
r(x)=tan(x) is an odd function since tan(-x)=-tan(x).
s(x)=csc(x) is an odd function since csc(-x)=-csc(x).
So the only contender seems to be C.
Let's check. To check we have to plug in (-x) in place of (x) and see if we get the same function back since we are looking for an even function.
Replace (x) with (-x):
since cosine is even; that is cos(-u)=cos(u) where u in this case is 
.
So f is even.
Answer: 47.86
Step-by-step explanation:
tan x =42/38
tan x= 1.105
x= 47.86
Answer:
Just to recap, an equation has no solution when it results in an incorrect "equation".
For example:
Equation: x+3 = x+4
Subtract x: 3 = 4???
But clearly, 3 is not equal to 4, so this equation has NO SOLUTION.
Now onto our problem:
13y+2-2y = 10y+3-y
11y+2 = 9y+3
2y=1
y=1/2
9(3y+7)-2 = 3(-9y+9)
27y+61 = -27y+27
54y = -34
y = -34/54
32.1y+3.1+2.4y-8.2=34.5y-5.1
34.5-5.1=34.5y-5.1
5.1=5.1
infinite solutions
5(2.2y+3.4) = 5(y-2)+6y
11y+17 = 11y-10
17 = -10??
That's not true, so the option "5(2.2y+3.4) = 5(y-2)+6y" has no solution.
Let me know if this helps
