Question

A club is choosing 2 members to serve on a committee. The club has nominated 3 women and 3 men. Based on chance alone, what is the probability that one woman and one man will be chosen to be on the committee

Answer 1

Answer: 0.6

Step-by-step explanation:

Given

There are 3 women and 3 men available to form a 2 member committee.

No of ways, a man can be chosen are $3$

Similarly, no of ways a woman can be chosen are 3

Therefore, probability of choosing 2 members i.e. 1 man and 1 women is

$\Rightarrow P=\dfrac{3}{6}\times \dfrac{3}{5}$

If the order matter, then

$\Rightarrow P=2\times \dfrac{3\times 3}{6\times 5}\\\\\Rightarrow P=0.6$