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Ivahew [28]
3 years ago
9

Find the circumference and area of a circle with a diameter of 14 inches. Leave your answers in terms of pi. C = 14π; A = 49π. C

= 7π; A = 28π. C = 14π; A = 28π. C = 7π; A = 49π
Mathematics
2 answers:
Olenka [21]3 years ago
5 0
Given:
diameter = 14 inches
radius = 14 inches / 2 = 7 inches

Circumference of a circle = 2 π r = 2 * π * 7inches = 14 inches * π

Area of a circle = π r² = π * (7in)² = π * 49in² 

C = 14π    and   A = 49π
RSB [31]3 years ago
5 0

Answer:

C = 14π    and   A = 49π

Step-by-step explanation:

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For what values of θ on the polar curve r=θ, with 0≤θ≤2π , are the tangent lines horizontal? Vertical?
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Given that r=\theta, then r'=1

The slope of a tangent line in the polar coordinate is given by:

m= \frac{r'\sin\theta+r\cos\theta}{r'\cos\theta-r\sin\theta}

Thus, we have:

m= \frac{\sin\theta+\theta\cos\theta}{\cos\theta-\theta\sin\theta}



Part A:

For horizontal tangent lines, m = 0.

Thus, we have:

\sin\theta+\theta\cos\theta=0 \\  \\ \theta\cos\theta=-\sin\theta \\  \\ \theta=- \frac{\sin\theta}{\cos\theta} =-\tan\theta

Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are horizontal are:

</span><span>θ = 0

</span>θ = <span>2.02875783811043
</span>
θ = <span>4.91318043943488



Part B:

For vertical tangent lines, \frac{1}{m} =0

Thus, we have:

\cos\theta-\theta\sin\theta=0 \\  \\ \Rightarrow\theta\sin\theta=\cos\theta \\  \\ \Rightarrow\theta= \frac{\cos\theta}{\sin\theta} =\sec\theta

</span>Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are vertical are:

</span>θ = <span>4.91718592528713</span>
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The answer is A your answer
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algol13

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Step-by-step explanation:

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