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Misha Larkins [42]
3 years ago
13

2⁄5 of 3⁄4= ..... what this equal

Mathematics
2 answers:
Katyanochek1 [597]3 years ago
6 0

Answer:

3/10

Step-by-step explanation:

Of means multiply

2/5 * 3/4

Rewriting

2/4 * 3/5

1/2*3/5

3/10

SIZIF [17.4K]3 years ago
3 0

Answer:

3/10

Step-by-step explanation:

No <3

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g A sample of 3 items is chosen at random from a box containing 20 items, out of which 4 are defective. Let X be the number of d
professor190 [17]

Answer:

The variance and standard deviation of <em>X</em> are 0.48 and 0.693 respectively.

The variance and standard deviation of (20 - <em>X</em>) are 0.48 and 0.693 respectively.

Step-by-step explanation:

The variable <em>X</em> is defined as, <em>X</em> = number of defective items in the sample.

In a sample of 20 items there are 4 defective items.

The probability of selecting a defective item is:

P (X)=\frac{4}{20}=0.20

A random sample of <em>n</em> = 3 items are selected at random.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 3 and <em>p </em>= 0.20.

The variance of a Binomial distribution is:

V(X)=np(1-p)

Compute the variance of <em>X</em> as follows:

V(X)=np(1-p)=3\times0.20\times(1-0.20)=0.48

Compute the standard deviation (σ (X)) as follows:

\sigma (X)=\sqrt{V(X)}=\sqrt{0.48}=0.693

Thus, the variance and standard deviation of <em>X</em> are 0.48 and 0.693 respectively.

Now compute the variance of (20 - X) as follows:

V(20-X)=V(20)+V(X)-2Cov(20,X)=0+0.48-0=0.48

Compute the standard deviation of (20 - X) as follows:

\sigma (20-X)=\sqrt{V(20-X)} =\sqrt{0.48}0.693

Thus, the variance and standard deviation of (20 - <em>X</em>) are 0.48 and 0.693 respectively.

3 0
3 years ago
2. Write (and do not solve) a word problem for the following inequality. 3(1/2x-6). &gt;- 70
Feliz [49]

Answer:

Step-by-step explanation:

hope this helped

3 0
3 years ago
Solve the proportional<br> equation below:<br> x/4 = x-6/3
aleksandrvk [35]
<h2><u>PROPORTIONAL EQUATION</u></h2><h3>Exercise</h3>

Apply the means-extremes property of proportions: this allows you to cross multiply:

                \boxed{\mathsf{\dfrac{x}{4} = \dfrac{x - 6}{3}}}

\mathsf{\dfrac{x}{4} \searrow \dfrac{x - 6}{3}}      ‏‏‎      ‏‏‎‎      \mathsf{\dfrac{x}{4} \nearrow \dfrac{x-6}{3}}‏‏‎‎

             \boxed{\mathsf{3x = 4(x - 6)}}

Apply the distributive property:

\mathsf{3x = 4(x-6)}

\mathsf{3x = 4(x) - 4(6)}

\mathsf{3x = 4x - 24}

Add 24 to both sides:

\mathsf{3x + 24 = 4x - 24 + 24}

\mathsf{3x + 24 = 4x}

Substract 3x to both sides

\mathsf{3x - 3x + 24 = 4x - 3x}

\mathsf{24 = 4x - 3x}

\large{\boxed{\mathsf{24 = x}}}

‎      ‏‏‎

<h3><u>Answer</u>. The value of x = 24.</h3>

‎      ‏‏‎

8 0
3 years ago
C = x + a / b solve for the x
Juli2301 [7.4K]

Answer:

x= C-a/b

Step-by-step explanation: Ik alllLlLLlllLlLL

(my other account is actingqueen2468 but i forgot my password)

4 0
3 years ago
Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule
Sergeeva-Olga [200]

Answer:

First term: 5

Fourth term: 5 1/2

Tenth term: 6 1/2

Step-by-step explanation:

Let's find the first, fourth and tenth terms of the arithmetic sequence described by the given rule:

A(n) = 5 + (n-1) (1/6)

First term:

A(1) = 5 + (1-1) (1/6)

A(1) = 5 + (0) (1/6)

A(1) = 5

Fourth term:

A(4) = 5 + (4-1) (1/6)

A(4) = 5 + (3) (1/6)

A(4) = 5 + 3/6 = 5 3/6 = 5 1/2 (simplifying)

Tenth term:

A(10) = 5 + (10-1) (1/6)

A(10) = 5 + (9) (1/6)

A (10) = 5 + 9/6 = 6 3/6 = 6 1/2 (simplifying)

5 0
3 years ago
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