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guapka [62]
3 years ago
12

I NEED HELP ASAP DUE IN 3 MINUTES WHOEVER ANSWERS IT RIGHT GETS BRIANIST

Mathematics
1 answer:
Damm [24]3 years ago
8 0

Answer:

It is D.

Step-by-step explanation:

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Which expressions are equivalent to the one below? Check all that apply.<br><br>log 2 - log 6
Marina CMI [18]

Answer:

Given the expression: log 2 -log 6

Use the logarithmic rule :

\log(\frac{m}{n}) = \log m - \log n

\log x^n = n\log x

Use the above rule to solve the expression:

\log 2 -\log 6 = \log \frac{2}{6} = \log \frac{1}{3}   [∴\log(\frac{m}{n}) = \log m - \log n ]

or

\log 2 -\log 6 =\log 2+ \log 6^{-1} = \log 2 + \log \frac{1}{6}     [∴\log x^n = n\log x ]

or

value of : log 2 -log 6 = 0.30102999566 - 0.77815125038 = -0.47712125472



7 0
3 years ago
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An economist is interested in studying the spending habits of consumers in a particular region. The population standard deviatio
Lena [83]

Answer:

The  width is  w = \$ 729.7

Step-by-step explanation:

From the question we are told that

   The population standard deviation is  \sigma =  \% 1,000

    The  sample size is  n  = 50

    The sample mean  is  \= x  =  \$ 15,000

Given that the confidence level is  99% then the level of significance is mathematically represented as  

               \alpha  =  100 - 99

=>            \alpha  =  1\%

=>             \alpha  = 0.01

Next we obtain the critical value of  \frac{\alpha }{2} from the normal distribution table, the value is

             Z_{\frac{\alpha }{2} } = Z_{\frac{0.01 }{2} } =  2.58

Generally margin of error is mathematically represented as

             E =  Z_{\frac{\alpha }{2} *  \frac{\sigma }{\sqrt{n} }

substituting values

              E = 2.58 *  \frac{1000 }{\sqrt{50} }

              E = 2.58 *  \frac{1000 }{\sqrt{50} }

               E = 364.9

The width of the 99% confidence interval is mathematically evaluated as

         w = 2 * E

substituting values

          w = 2 * 364.9

          w = \$ 729.7

5 0
3 years ago
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Stolb23 [73]

Answer:

Step-by-step explanation:

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