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Paraphin [41]
3 years ago
11

Question in the photo

Mathematics
2 answers:
melisa1 [442]3 years ago
3 0

Answer:

14

Step-by-step explanation:

To make this not a function, the same input would need to go to two different outputs

so the input would need to be 5 ,17, or 14

tekilochka [14]3 years ago
3 0
C.14
You can’t have the two of the same inputs.
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9. The figure shows a rectangle with its length and
lora16 [44]

Answer:

875cm^2

Step-by-step explanation:

since opposite sides are equal

3x-y=2x+y

x=2y                                                      

y=x/2                                                                      ....(i)

thus new length=2x+y

=2x+(x/2)                                                              [using (i)]

=(4x+x)/2

l=5x/2                                                                   .....(ii)

now,

perimeter=2(l+b)=120cm

l+b=60cm            

from figure and using (ii)

[5x/2]+2x-3=60

[5x+4x-6]/2=60

9x-6=120

9x=126

x=126/9

x=14                                                                 ..........(iii)

substitute (iii) in (i)

y=14/2

y=7                                                                  ...........(iv)

From figure,

length=2x+y                                                   [using (iii) and (iv)]

=2x14+7

length=35cm

breadth=2x-3

=2x14-3                                                          ....[using(iii)]

=28-3

breadth=25cm

now,

Area=lxb

=35x25

=875cm^2

7 0
3 years ago
For number 6, evaluate the definite integral.
maks197457 [2]
\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{(8+2x)^2}}\cdot dx\impliedby \textit{now, let's do some substitution}\\\\
-------------------------------\\\\
u=8+2x\implies \cfrac{du}{dx}=2\implies \cfrac{du}{2}=dx\\\\
-------------------------------\\\\

\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{u^2}}\cdot \cfrac{du}{2}\implies \cfrac{1}{2}\int\limits_{0}^{28}\ u^{-\frac{2}{3}}\cdot du\impliedby 
\begin{array}{llll}
\textit{now let's change the bounds}\\
\textit{by using } u(x)
\end{array}\\\\
-------------------------------\\\\
u(0)=8+2(0)\implies u(0)=8
\\\\\\
u(28)=8+2(28)\implies u(28)=64

\bf \\\\
-------------------------------\\\\
\displaystyle  \cfrac{1}{2}\int\limits_{8}^{64}\ u^{-\frac{2}{3}}\cdot du\implies \cfrac{1}{2}\cdot \cfrac{u^{\frac{1}{3}}}{\frac{1}{3}}\implies \left. \cfrac{3\sqrt[3]{u}}{2} \right]_8^{64}
\\\\\\
\left[ \cfrac{3\sqrt[3]{(2^2)^3}}{2} \right]-\left[ \cfrac{3\sqrt[3]{2^3}}{2}  \right]\implies \cfrac{12}{2}-\cfrac{6}{2}\implies 6-3\implies 3
3 0
2 years ago
Three-fourths was subtracted from a number, and then 5 1/4 was added to the result. The sum was -7.
Alika [10]

Answer:

1 1/4 is the answer

Step-by-step explanation:

Hope this helps :))

6 0
3 years ago
Malik’s weekly pay varies directly to the number of hours he works as a lifeguard. His weekly pay is $246.50 when he works 17 ho
mash [69]

Answer:

Step-by-step explanation:

6 0
3 years ago
A deli is offering two specials. The roast beef special gives a profit of $2.30 per sandwich, and the turkey special gives a pro
nikklg [1K]

Answer:

The constraints are as follows;

1) 2·x + 2·y ≤ 120

2) 3·x + 4·y ≤ 160

3) x = 2.30

4) y = 3.10

5) P = 2.3·x + 3.10

Step-by-step explanation:

The question is a word problem, with the analysis as follows;

The profit from the roast beef special per sandwich = $2.30

The profit from the turkey special per sandwich = $3.10

The number of slices of bread in the roast beef special = Two slices

The number of slices of cheese in the roast beef special = Three slices

The number of slices of bread in the turkey special = Two slices

The number of slices of cheese in the turkey special = Four slices

The number of slices of bread the deli has  = 120 slices

The number of slices of cheese the deli has = 160 slices

Let 'x' and represent the number of roast beef special and 'y' represent the number of turkey special the deli makes, then we have the constraints as follows;

For the number of slices of bread used;

2·x + 2·y ≤ 120...(1)

For the number of slices of cheese used;

3·x + 4·y ≤ 160...(2)

x = 2.30

y = 3.10

The profit 'P' is given by the following equation

P = 2.3·x + 3.10.

5 0
2 years ago
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