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Reptile [31]
3 years ago
15

Solve for q. 5q + 2p + 4 = 3q – 8​

Mathematics
2 answers:
Sergio039 [100]3 years ago
7 0

q =  - p - 6

5q + 2p + 4 - 3q =  - 8 \\ 2q + 2p + 4 =  - 8 \\ 2q + 4 =  - 8 - 2p \\ 2q =  - 8 - 2p - 4 \\ 2q =  - 12  -  2p \\  \frac{2q}{2}  =  \frac{ - 2p - 12}{2}  \\ q =  \frac{ - 2p - 12}{2}  \\ q =  - p - 6

bulgar [2K]3 years ago
5 0

Answer:

q = -p-6

Step-by-step explanation:

=> 5q+2p+4 = 3q-8

(Combining like terms)

=>5q-3q = -2p-8-4

=> 2q = -2p -12

=> 2q = 2(-p-6)

Dividing both sides by 2

=> q = -p-6

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Answer:

49

Step-by-step explanation:

(351-8)/7 = 49

7 0
3 years ago
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12345678910 Using the greatest common factor for the terms, how can you write 80 + 32 as a product?
Romashka-Z-Leto [24]
Find the GCF of 80 and 32.  

I'd start by identifying possible integer factors of both 80 and 32:
80:  {1,2,4,5,8,10,16,20, 40, 80}

32:  {1, 2,4, 8, 16, 32}

Working backwards, we see that the first factor that is represented in both lists is 16.  Is 80 evenly divisible by 16?  Yes; the quotient is 5.
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You could writet 80 + 32 as 16(5 + 2).  This is a product equal to 112, just as 80 + 32 = 112.
5 0
3 years ago
A bag contains 10 red marbles, 15 yellow marbles, 5 green marbles, and 20 blue marbles. Two marbles are drawn from the bag.
kherson [118]

Answer:

It is the third option: (10C1) (20C1( / 50C2.

Step-by-step explanation:

The number of ways of selecting 2 marbles = the number of combination of any 2 marbles in the 50 marbles in the bag and this is 50C2. It is combinations because the order of drawing the marbles does not matter.

The number of combinations  of one being red and the other blue =  10C1 times 20C1.

So the answer is (10C1) (20C1( / 50C2.

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3 years ago
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Strike441 [17]
Wow I don't get it either but my guess would be 9,6...sorry....
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7 d^2 +10 when d = 3
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Answer:

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Step-by-step explanation:

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3 years ago
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