The total area of the room is 37.6376 and the no. of cans required to paint the wall is 3 cans.
The measurement of two of the walls is 2.86 metres and 3.16 metre
Area of the two walls = 2(length x breadth)
Area = 2(2.86 x 3.16) = 18.0752 m²
The measurement of the other two walls is 2.86 metres and 3.42 metres
Area of the two walls = 2(length × breadth)
Area = 2(2.86 × 3.42) = 19.5624 m²
Total area = 18.0752 + 19.5624 = 37.6376 m²
If one can of paint can cover 15 m², the no. of cans required to paint the bedroom will be
No. of cans = Total area/Area covered by one can of paint
No. of cans = 37.6376/15 = 2.5091 = 3 cans (approx.)
Answer:
<h2>The time needed is 10 months.</h2>
Step-by-step explanation:
The given points are (0, 3500) and (5, 1750).
First, we use the formula below to find the slope of the line
Which means the function is deacrasing with a ratio of 350 feet per month.
Now, we use the slope and one point to find the equation
This linear function shows that the situation started at the y-intecept (0, 3500), which means the month 0 had already 3500 feet. In other words, the total distance is 3500 feet. Now, the x-intercept will tell us the time needed to travel that distance.
Therefore, the time needed is 10 months.
Answer: 1/3
Explanation:
1/12 of the squad are suspended:
1/12 x 24 = 24/12 = 2
So 2 player are suspended
24 - 2 = 22 player
And some are injured leaving 14 left to play:
22 - 14 = 8 players injured
So 8/24 is the fraction of injured player.
But 8/24 = 1/3 so we can say 1/3 of the whole squad are injured.
Example 1
Write y = x2 + 4x + 1 using function notation and evaluate the function at x = 3.
Solution
Given, y = x2 + 4x + 1
By applying function notation, we get
f(x) = x2 + 4x + 1
Evaluation:
Substitute x with 3
f (3) = 32 + 4 × 3 + 1 = 9 + 12 + 1 = 22
Example 2
Evaluate the function f(x) = 3(2x+1) when x = 4.
Solution
Plug x = 4 in the function f(x).
f (4) = 3[2(4) + 1]
f (4) = 3[8 + 1]
f (4) = 3 x 9
f (4) = 27
Example 3
Write the function y = 2x2 + 4x – 3 in function notation and find f (2a + 3).
Solution
y = 2x2 + 4x – 3 ⟹ f (x) = 2x2 + 4x – 3
Substitute x with (2a + 3).
f (2a + 3) = 2(2a + 3)2 + 4(2a + 3) – 3
= 2(4a2 + 12a + 9) + 8a + 12 – 3
= 8a2 + 24a + 18 + 8a + 12 – 3
= 8a2 + 32a + 27
Answer:
Sachet town is 12km from the airport
Step-by-step explanation:
In this question, we are asked to calculate the distance from sachet town to the airport.
This can be calculated by referring to a diagrammatic representation. Please check attached file.
Let’s proceed with the calculations however.
From the question, we can see that we have formed a Right angled triangle from the diagram and we need to calculate the distance x.
Mathematically;
x^2 + 16^2 = 20^2
x^2 = 20^2 - 16^2
x^2 = 400 - 256
x^2 = 144
x = sq.rt of 144
x = 12km
