Answer:
In terms of efficient use of memory: Best-fit is the best (it still have a free memory space of 777KB and all process is completely assigned) followed by First-fit (which have free space of 777KB but available in smaller partition) and then worst-fit (which have free space of 1152KB but a process cannot be assigned). See the detail in the explanation section.
Explanation:
We have six free memory partition: 300KB (F1), 600KB (F2), 350KB (F3), 200KB (F4), 750KB (F5) and 125KB (F6) (in order).
Using First-fit
First-fit means you assign the first available memory that can fit a process to it.
- 115KB will fit into the first partition. So, F1 will have a remaining free space of 185KB (300 - 115).
- 500KB will fit into the second partition. So, F2 will have a remaining free space of 100KB (600 - 500)
- 358KB will fit into the fifth partition. So, F5 will have a remaining free space of 392KB (750 - 358)
- 200KB will fit into the third partition. So, F3 will have a remaining free space of 150KB (350 -200)
- 375KB will fit into the remaining partition of F5. So, F5 will a remaining free space of 17KB (392 - 375)
Using Best-fit
Best-fit means you assign the best memory available that can fit a process to the process.
- 115KB will best fit into the last partition (F6). So, F6 will now have a free remaining space of 10KB (125 - 115)
- 500KB will best fit into second partition. So, F2 will now have a free remaining space of 100KB (600 - 500)
- 358KB will best fit into the fifth partition. So, F5 will now have a free remaining space of 392KB (750 - 358)
- 200KB will best fit into the fourth partition and it will occupy the entire space with no remaining space (200 - 200 = 0)
- 375KB will best fit into the remaining space of the fifth partition. So, F5 will now have a free space of 17KB (392 - 375)
Using Worst-fit
Worst-fit means that you assign the largest available memory space to a process.
- 115KB will be fitted into the fifth partition. So, F5 will now have a free remaining space of 635KB (750 - 115)
- 500KB will be fitted also into the remaining space of the fifth partition. So, F5 will now have a free remaining space of 135KB (635 - 500)
- 358KB will be fitted into the second partition. So, F2 will now have a free remaining space of 242KB (600 - 358)
- 200KB will be fitted into the third partition. So, F3 will now have a free remaining space of 150KB (350 - 200)
- 375KB will not be assigned to any available memory space because none of the available space can contain the 375KB process.
Answer:
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Explanation:
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The purpose of the transmission control protocol is to ensure the integrity of the communication.
The TCP/IP network architecture also refers to the Internet architecture. The Transmission Control Protocol (TCP) is a transport layer protocol, and the Internet Protocol (IP) is a network layer protocol.
<h3>What is Transmission control protocol ?</h3>
Transmission Control Protocol, or TCP, is a communications standard that enables computer hardware and software to exchange messages over a network. It is intended to send packets over the internet and make sure that data and messages are successfully delivered through networks.
- TCP's (Transmission Control Protocol) purpose is to regulate data transport so that it is dependable. Connection management, dependability, flow control, and congestion control are the four fundamental TCP functions. Connection initialization (a three-way handshake) and termination are included in connection management.
Learn more about Transmission control protocol here:
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You can edit the contents of a cell directly in the cell. You can also edit the contents of a cell by typing in the formula bar.
When you edit the contents of a cell, Excel is operating in Edit mode. Some Excel features work differently or are unavailable in Edit mode.
Answer:
Explanation:
data is a statement like
data 10,20, 30 , 40 , 50, 60 , 70, 80
\\the numbers represent ages.
For x := 1 to end of data do a[x]:=read(data)
\\ This is a comment. You could do this much easier if you just use three if statements rather than the if then else.
minor:=0;adult:=0;senior:=0;
while a[x] <> 0 do begin
age:= a[x]
if age < 19 then minor:=minor + 1;
If age > 18 then if age < 65 the adult:=adult + 1;
if age > 64 then senior := senior + 1;
end;
I have not declared the variables anywhere. That depends on what language you are using. The key step you want are the three if statements. How you find out what's in them is another matter.
