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2 years ago

Hehe!! I need help w/ this. Can someone do this whole thing for brainliest?

Mathematics

1 answer:

Alla [95]2 years ago

6 0

Answer:

Step-by-step explanation:

1-55

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A playground is being designed where children can interact with their friends in certain combinations. If there is 1 child, ther

mariarad [96]

<h2>Answer:</h2>

Recursive equation for the pattern followed is given by,

$a_{n}=a_{n-1}+(n-1)^{2}$

<h2>Step-by-step explanation:</h2>

In the question,

The number of interaction for 1 child = 0

Number of interactions for 2 children = 1

Number of interactions for 3 children = 5

Number of interaction for 4 children = 14

So,

We need to find out the pattern for the recursive equation for the given conditions.

So,

We see that,

$a_{1}=0\\a_{2}=1\\a_{3}=5\\a_{4}=14\\$

Therefore, on checking, we observe that,

$a_{n}=a_{n-1}+(n-1)^{2}$

On checking the equation at the given values of 'n' of, 1, 2, 3 and 4.

At,

n = 1

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{1}=a_{1-1}+(1-1)^{2}\\a_{1}=0+0=0\\a_{1}=0$

which is true.

At,

n = 2

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{2}=a_{2-1}+(2-1)^{2}\\a_{2}=a_{1}+1\\a_{2}=1$

Which is also true.

At,

n = 3

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{3}=a_{3-1}+(3-1)^{2}\\a_{3}=a_{2}+4\\a_{3}=5$

Which is true.

At,

n = 4

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{4}=a_{4-1}+(4-1)^{2}\\a_{4}=a_{3}+9\\a_{4}=14$

This is also true at the given value of 'n'.

Therefore, the recursive equation for the pattern followed is given by,

$a_{n}=a_{n-1}+(n-1)^{2}$

3 0

2 years ago

What is the answer to 198=-4x+2(-6x+3)

liq [111]

Answer: x = 12

i hope this helps

7 0

2 years ago

Liz wants to estimate the percentage of people who rent their home. She surveys 320 individuals and finds that 176 rent their ho

SOVA2 [1]

Answer: 0.065

Step-by-step explanation:

Given : Sample size : n= 320

The sample proportion of people who rent their home : $p=\dfrac{176}{320}=0.55$

Significance level : $\alpha:1-0.98=0.02$

Then , Critical value : $z_{\alpha/2}=2.33$

The formula to find the margin of error : -

$E=z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}\\\\\Rightarrow\ E=(2.33)\sqrt{\dfrac{0.55(1-0.55)}{320}}\\\\\Rightarrow\ E=0.064799034281\approx0.065$

Hence, the margin of error for the confidence interval for the population proportion with a 98% confidence level =0.065

4 0

2 years ago

What is the constant rate of change from the graph?

Lady_Fox [76]

Your answer would be C. 2

3 0

2 years ago

Another Algebra problem i am too stupid to do

VARVARA [1.3K]

5 (x+4) ...................

8 0

2 years ago