Complete question is;
The terminal side of angle θ in standard position, intersects the unit circle at P(-10/26, -24/26). What is the value of csc θ?
Answer:
csc θ = -13/12
Step-by-step explanation:
We know that in a unit circle;
(x, y) = (cos θ, sin θ)
Since the the terminal sides intersects P at the coordinates P(-10/26, -24/26), we can say that;
cos θ = -10/26
sin θ = -24/26
Now we want to find csc θ.
From trigonometric ratios, csc θ = 1/sin θ
Thus;
csc θ = 1/(-24/26)
csc θ = -26/24
csc θ = -13/12
Answer:
We have function,

Standard Form of Sinusoid is

Which corresponds to

where a is the amplitude
2pi/b is the period
c is phase shift
d is vertical shift or midline.
In the equation equation, we must factor out 2 so we get

Also remeber a and b is always positive
So now let answer the questions.
a. The period is


So the period is pi radians.
b. Amplitude is

Amplitude is 6.
c. Domain of a sinusoid is all reals. Here that stays the same. Range of a sinusoid is [-a+c, a-c]. Put the least number first, and the greatest next.
So using that<em> rule, our range is [6+3, -6+3]= [9,-3] So our range</em> is [-3,9].
D. Plug in 0 for x.





So the y intercept is (0,-3)
E. To find phase shift, set x-c=0 to solve for phase shift.


Negative means to the left, so the phase shift is pi/4 units to the left.
f. Period is PI, so use interval [0,2pi].
Look at the graph above,
<h2>Andromeda galaxy is your answer </h2>
Answer:
57,505,708 x .165 =9488441.82 NA
57,505,708 x .3 = 17251712.4 Asia
17251712.4 - 9488441.82 = 7763270.58
That's how much larger asia is than north america
Step-by-step explanation: