I like to start by dividing the given number by 2, unless a larger factor is evident.
1386 = 2(693). It's pretty obvious that we can divide 693 by 3: 693=3(231).
Then we have 1386 = (2)(3)(231). Try the same procedure. Does 231 have any integer, prime factors? See how far you can take this factoring.
Answer:
62
Step-by-step explanation:
372÷6 is 62
Answer:
not arithmetic
Step-by-step explanation:
An arithmetic sequence has a common difference d between consecutive terms.
Given
= 2n² - 1
Substitute in n = 1, 2, 3, 4 to generate the first 4 terms of the sequence
= 2(1)² - 1 = 2 - 1 = 1
= 2(2)² - 1 = 8 - 1 = 7
= 2(3)² - 1 = 18 - 1 = 17
= 2(4)² - 1 = 32 - 1 = 31
check the difference between consecutive terms
7 - 1 = 6
17 - 7 = 10
31 - 17 = 14
The differences are not common hence not an arithmetic sequence
Answer: D) 18
Step-by-step explanation:
6 - x = -12
Subtract 6 from both sides.
-x = -18
Divide by -1 on both sides so as to isolate x.
x = 18
Consider this option:
1. formula is: S=0.5*d₁*d₂, where d₁;d₂ - the diagonals of the rhombus.
2. substituting the values into the formula: S=0.5*21*32=336 m².
answer: 336 m².
