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DerKrebs [107]
3 years ago
8

Can someone please help me with number 6 complete the statement the state the property illustrated by the statement

Mathematics
1 answer:
djyliett [7]3 years ago
8 0

Answer:

Eliminate redundant parentheses

( − 5 ) = 1 − 5 = 1

Divide both sides of the equation by the same term− 5 = 1

-5x/-5 = 1/-5

Simplify

Cancel terms that are in both the numerator and denominator

-5x/-5=1/-5     x=1/-5

Divide the numbers

x=-1/5

Step-by-step explanation:

ANSWER x=-1/5

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Solve 3x - 5 + x = 31.
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8 0
2 years ago
Read 2 more answers
What is the equation of a parabola with (−2, 4) as its focus and y = 6 as its directrix? Enter the equation in the box.
SOVA2 [1]
Notice the picture below

the directrix is above the focus point, meaning the parabola is vertical and is opening downwards

now, "p" is the distance from the vertex to the focus point or the directrix, so that means, the vertex is between those two fellows, over the axis of symmetry, x = -2, since "p" is 1 unit, that puts the vertex at -2,5

since the parabola is opening downwards, that means the "p" value is negative, so is -1

\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
(y-{{ k}})^2=4{{ p}}(x-{{ h}}) \\\\
\boxed{(x-{{ h}})^2=4{{ p}}(y-{{ k}}) }\\
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ({{ h}},{{ k}})\\\\
{{ p}}=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\
-----------------------------\\\\

\bf \begin{cases}
p=-1\\
h=-2\\
k=5
\end{cases}\implies (x-(-2))^2=4(-1)(y-5)
\\\\\\
(x+2)^2=-4(y-5)\implies 
-\cfrac{1}{4}(x+2)^2=y-5
\\\\\\
\boxed{-\cfrac{1}{4}(x+2)^2+5=y}

4 0
3 years ago
F(x) = √3x
Nataly_w [17]

The domain of the function is (\frac{f}{g})(x) = \frac{\sqrt[3]{3x}}{5x + 2} . x \ne -\frac 25

<h3>How to determine the domain and the restrictions?</h3>

The attached image represents the complete form of the question

The functions are given as:

f(x) = \sqrt[3]{3x}

g(x) = 5x + 2

The function (f/g)(x) is calculated using:

(\frac{f}{g})(x) = \frac{f(x)}{g(x)}

This gives

(\frac{f}{g})(x) = \frac{\sqrt[3]{3x}}{5x + 2}

The denominator cannot be 0.

So, we have:

5x + 2 \ne 0

Solve for x

x \ne -\frac 25

Hence, the domain of the function is (\frac{f}{g})(x) = \frac{\sqrt[3]{3x}}{5x + 2} . x \ne -\frac 25

Read more about domain at:

brainly.com/question/1770447

#SPJ1

4 0
1 year ago
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