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DerKrebs [107]
3 years ago
8

Can someone please help me with number 6 complete the statement the state the property illustrated by the statement

Mathematics
1 answer:
djyliett [7]3 years ago
8 0

Answer:

Eliminate redundant parentheses

( − 5 ) = 1 − 5 = 1

Divide both sides of the equation by the same term− 5 = 1

-5x/-5 = 1/-5

Simplify

Cancel terms that are in both the numerator and denominator

-5x/-5=1/-5     x=1/-5

Divide the numbers

x=-1/5

Step-by-step explanation:

ANSWER x=-1/5

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Answer:

To estimate the quotient, make the fractions "like" fractions. To do this, you need to make the fractions have the same denominator, and turn them into improper fractions.

Step-by-step explanation:

27\frac{2}{3} = 27 \frac{20}{30}

3\frac{9}{10} = 3\frac{27}{30}

Now the denominators are the same --> they are "like" fractions.

27\frac{20}{30} + 3\frac{27}{30} = ?

27\frac{20}{30} + 3\frac{27}{30} = (27 + 3) + (\frac{20}{30} + \frac{27}{30})

27\frac{20}{30} + 3\frac{27}{30} = (30) + (\frac{47}{30})

27\frac{20}{30} + 3\frac{27}{30} = (30) + (1 \frac{17}{30})

27\frac{20}{30} + 3\frac{27}{30} = 31 \frac{17}{30}

Your answer is 31\frac{17}{30}.

I hope this helps!

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4 years ago
Marcy makes 15 of 20 free throws at basketball practice. What is the probability that she will miss her free throw? Possible ans
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Answer:

3/4

Step-by-step explanation:

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An automobile manufacturer has given its car a 52.6 miles/gallon (MPG) rating. An independent testing firm has been contracted t
Arte-miy333 [17]

Answer:

Null hypothesis:\mu = 52.6  

Alternative hypothesis:\mu \neq 52.6  

z=\frac{52.8-52.6}{\frac{1.6}{\sqrt{250}}}=1.976    

p_v =2*P(z>1.976)=0.0482  

Since the p value is lower than the significance level wedon't have enough evidence to conclude that the true mean is significantly different from 52.6 MPG.

Step-by-step explanation:

Information provided

\bar X=52.8 represent the sample mean  for the MPG of the cars

\sigma=1.6 represent the population standard deviation

n=250 sample size  of cars

\mu_o =52.6 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test

Hypothesis

We need to conduct a hypothesis in order to check if the true mean of MPG is different from 52.6 MPG, the system of hypothesis would be:  

Null hypothesis:\mu = 52.6  

Alternative hypothesis:\mu \neq 52.6  

Since we know the population deviation the statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Calculate the statistic

Replacing we have this:

z=\frac{52.8-52.6}{\frac{1.6}{\sqrt{250}}}=1.976    

Decision

Since is a two tailed test the p value would be:  

p_v =2*P(z>1.976)=0.0482  

Since the p value is lower than the significance level wedon't have enough evidence to conclude that the true mean is significantly different from 52.6 MPG.

3 0
3 years ago
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