If 8 g of a radioactive substance are present initially and 2 yr later only 4 g remain, how much of the substance will be presen
t after 5 yrs?
1 answer:
Answer:
none
Step-by-step explanation:
8-4=4
if every 2 years, 4 gallons disappear
then every 1 year, 2 gallons disappear
meaning that by 5 years there will be no substance left.
(5*2=10)
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radius = diameter/2 = 24 m / 2 = 12 m
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Step-by-step explanation:
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39 + 0.16m = 25 + 0.24m
39 - 25 = 0.24m - 0.16m
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