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katrin [286]
2 years ago
7

If 8 g of a radioactive substance are present initially and 2 yr later only 4 g remain, how much of the substance will be presen

t after 5 yrs?
Mathematics
1 answer:
My name is Ann [436]2 years ago
7 0

Answer:

none

Step-by-step explanation:

8-4=4

if every 2 years, 4 gallons disappear

then every 1 year, 2 gallons disappear

meaning that by 5 years there will be no substance left.

(5*2=10)

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Y = -3x +10 3x +y = 5 substitution method
spayn [35]

Answer:

no solutions

Step-by-step explanation:

y = -3x +10

3x +y = 5

Substitute the first equation into the second equation

Let every instance of y in the second equation be replaced with -3x+10

3x+ (-3x+10) = 5

Combine like terms

10 =5

This is never true so there are no solutions

(These are parallel lines with the same slope but different y intercepts)

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2 years ago
Please answer questions 1-6 i’ll mark as brainliest<3
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Yea I’m good too much
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3 years ago
Help pls thank you!!!!!!
jasenka [17]

Answer:

relative minimum would be your awnser

4 0
3 years ago
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Find the GCF. 14abc and 28a2b2c3
Zarrin [17]

The greatest common factor is the largest factor that both terms share.

First, start with the coefficients, 14 and 28. The largest factor they both share is 14. 14 x 1 = 14, 14 x 2 = 28.

Next we move to the variables, abc and a²b²c³. The largest factor the both share is abc, all to the power of 1.

So, your GCF and final answer is 14abc

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Dovator [93]

I think d but im not sure


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3 years ago
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