The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Work done (Wd) =?
<h3>How to determine the spring constant</h3>
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Spring constant (K) =?
F = Ke
Divide both sides by e
K = F/ e
K = 3 / 0.6
K = 5 pound/foot
Thus, the spring constant of the spring is 5 pound/foot
<h3>How to determine the work done</h3>
- Spring constant (K) = 5 pound/foot
- Extention (e) = 0.7 feet
- Work done (Wd) =?
Wd = ½Ke²
Wd = ½ × 5 × 0.7²
Wd = 2.5 × 0.49
Wd = 1.23 foot-pound
Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound
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The second store price is cheaper beacuse 16% of 573 gives off $91.68 and when u do that u get $481.32 so 458.40 is cheaper.
Answer:
one gadget costs $15.80
Step-by-step explanation:
Let w = cost of one widget
Let g = cost of one gadget
Given:
- Five widgets and three gadgets cost $109. 90
⇒ 5w + 3g = 109.9
Given:
- One widget and four gadgets cost $75. 70
⇒ w + 4g = 75.7
Rewrite w + 4g = 75.7 to make w the subject:
⇒ w = 75.7 - 4g
Substitute into 5w + 3g = 109.9 and solve for g:
⇒ 5(75.7 - 4g) + 3g = 109.9
⇒ 378.5 - 20g + 3g = 109.9
⇒ 378.5 - 109.9 = 20g - 3g
⇒ 268.6 = 17g
⇒ g = 15.8
Therefore, one gadget costs $15.80
To find the cost of one widget, substitute the found value for g into
w = 75.7 - 4g and solve for w:
⇒ w = 75.7 - 4(15.8)
⇒ w = 75.7 - 63.2
⇒ w = 12.5
Therefore, one widget costs $12.50
Answer:
Solution given:
Increase percentage=
%
=4%
<u>the percentage </u><u>increase</u><u> </u><u>is</u><u> </u><u>4</u><u>%</u><u>.</u>
