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3 years ago

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Tammy is 8 years older than mike. jane is twice as old as mike. the sum of there ages is 52

1 answer:

docker41 [41]3 years ago

7 0

Answer:

Hey Xzavier! You're in my class!! Probably shouldn't use your real name on a cheating website... I mean ya... it's funny as hell and gave me a REALLY great laugh but our teachers know websites like these exist and by using your real name you're going to get caught eventually. I'm not a rat and I won't tell Mrs. Furnia but for future reference, use a screen name...

Step-by-step explanation:

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Simplify the sum (complex fraction)

andrey2020 [161]

I got 2d^4-2d^2-5/d^2

5 0

3 years ago

Read 2 more answers

The museum charges $14 for adult admission and $11 for each child. the museum bill for a school field trip was $896.

lord [1]

14x + 11y = 896

x = number of adults
y= number of kids
if nine adults went then 70 kids went

6 0

3 years ago

If S_1=1,S_2=8 and S_n=S_n-1+2S_n-2 whenever n≥2. Show that S_n=3⋅2n−1+2(−1)n for all n≥1.

Snezhnost [94]

You can try to show this by induction:

• According to the given closed form, we have $S_1=3\times2^{1-1}+2(-1)^1=3-2=1$ , which agrees with the initial value <em>S</em>₁ = 1.

• Assume the closed form is correct for all <em>n</em> up to <em>n</em> = <em>k</em>. In particular, we assume

$S_{k-1}=3\times2^{(k-1)-1}+2(-1)^{k-1}=3\times2^{k-2}+2(-1)^{k-1}$

and

$S_k=3\times2^{k-1}+2(-1)^k$

We want to then use this assumption to show the closed form is correct for <em>n</em> = <em>k</em> + 1, or

$S_{k+1}=3\times2^{(k+1)-1}+2(-1)^{k+1}=3\times2^k+2(-1)^{k+1}$

From the given recurrence, we know

$S_{k+1}=S_k+2S_{k-1}$

so that

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 2\left(3\times2^{k-2}+2(-1)^{k-1}\right)$

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 3\times2^{k-1}+4(-1)^{k-1}$

$S_{k+1}=2\times3\times2^{k-1}+(-1)^k\left(2+4(-1)^{-1}\right)$

$S_{k+1}=3\times2^k-2(-1)^k$

$S_{k+1}=3\times2^k+2(-1)(-1)^k$

$\boxed{S_{k+1}=3\times2^k+2(-1)^{k+1}}$

which is what we needed. QED

6 0

3 years ago

Which of these numbers are perfect squares or perfect cubes? Select the THREE answers that apply. 8 16 32/ 64 128 6 Omestian 12

Murljashka [212]

Answer:

8, 16, 64

Step-by-step explanation:

8 = 2^3 . . . a perfect cube

16 = 4^2 . . . a perfect square

32 = 2^5 . . . neither a cube nor a square

64 = 2^6 = 4^3 = 8^2 . . . both a perfect cube and a perfect square

128 = 2^7 . . . neither a cube nor a square

8 0

3 years ago

Last year at Sarah's bakery she sold 38 birthday cakes for $57 per cake . She spent 1/2 of that money on ingredients for baking

Andrei [34K]

Sarah spent $1,083 because $57*38=$2,166 and $2,166/2=$1083

7 0

3 years ago