Answer:
y=1x+8
Step-by-step explanation:
Let's start with the general slope-intercept equation of a line, which is defined as:
(y-b)=m*(x-a), where:
(a,b) is a point belonging to the line, and, m is the line's slope.
The equation for the given line is:
y=x+11, which can be re-written as:
(y-11)=1(x-0)
This means that the slope of this line is m=1, and that a point belonging to the line is (0,11).
Since parallel lines are defined as lines with the same slope, then for the second line, we need to establish m=1.
Becuase the point (-6,2) is a point belonging to the second line, then we can express the general equation (y-b)=m*(x-a) as:
(y-2)=1(x-(-6)) which we can re-write as:
y=1(x-(-6))+2
y=1x+6+2
y=1x+8
In conclusion, the equation of a line that passes through the point (-6,2) and is parallel to the given line, can be described by the following equation in its slope-intercept form: y=1x+8.
