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2 years ago

100PTS AND BRAINLIEST PLEASE HELP

Mathematics

2 answers:

Verdich [7]2 years ago

8 0

Answer:

b- ∠ACB ≅ ∠E'C'D'; ∠D'E'C' ≅ ∠BAC

Step-by-step explanation:

Correct On test !!

Elina [12.6K]2 years ago

4 0

Answer:

b- ∠ACB ≅ ∠E'C'D'; ∠D'E'C' ≅ ∠BAC

Step-by-step explanation:

I got it right on the test :))

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Which expression is equivalent to 21 × 7?

madreJ [45]

7 x 21 is equivalent to 21 x 7
also 3 x 49

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3 years ago

Which expression is equivalent

gtnhenbr [62]

Answer:

Option B is correct.

$\frac{81m^2n^5}{8}$ is equivalent to $\frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}$

Step-by-step explanation:

Given expression: $\frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}$

Using exponents power:

$(ab)^n = a^nb^n$

$(a^n)^m = a^{nm}$

$a^m \cdot a^n = a^{m+n}$

Given: $\frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}$

Apply exponent power :

⇒ $\frac{3^4 (m^{-1})^4(n^2)^4}{2^3(m^{-2})^3 n^3}$

⇒ $\frac{81 m^{-4}n^8}{8m^{-6}n^3} = \frac{81 m^{-4} \cdot m^6 n^8 \cdot n^{-3}}{8}$

⇒ $\frac{81 m^{-4+6} n^{8-3}}{8} = \frac{81 m^2 n^5}{8} = \frac{81m^2 n^5}{8}$

Therefore, the expression which is equivalent to $\frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}$ is, $\frac{81m^2 n^5}{8}$

4 0

3 years ago

Read 2 more answers

PLEASE HELP ME OUT!!!

zloy xaker [14]

38 just count the sides, thats perimeter

5 0

3 years ago

Can someone help me please I’m confused!!!

Soloha48 [4]

Answer:

10) -1

11) 1/2 or 0.5

12) -1/5 or -0.2

13) -13/6 or -2.166666666

14) -1/8 or -0.125

15) 1/2 or 0.5

hope it helps;)

good luck!

4 0

3 years ago

C = 5/9 × (F – 32)<br><br><br> 122°F = °C

swat32

Answer:

In Celsius the degree is 50°

Step-by-step explanation:

Put the 122° into the equation given.

4 0

2 years ago