Question

Please hlep x^2+6x+1=0

Answer 1

Answer:

Substitute into the quadratic formula

-6 ± √32 / 2

= -3 ± √16

= 1 and -1 are the answer

Answer 2

Answer:

x = - 3 ± 2$\sqrt{2}$

Step-by-step explanation:

Given

x² + 6x + 1 = 0 ( subtract 1 from both sides )

x² + 6x = - 1

Using the method of completing the square

add/ subtract ( half the coefficient of the x- term)² to both sides

x² + 2(3)x + 9 = - 1 + 9

(x + 3)² = 8 ( take the square root of both sides )

x + 3 = ± $\sqrt{8}$ = ± 2$\sqrt{2}$ ( subtract 3 from both sides )

x = - 3 ± 2$\sqrt{2}$

Then

x = - 3 - 2$\sqrt{2}$ , x = - 3 + 2$\sqrt{2}$