There are a total of five theorems congruent triangles. They are summarized as:
<h3>What are the definitions of the Theorems of Congruent Triangles?</h3>
SAS - Side Angle Side
According to the SAS rule, two triangles are said to be congruent if any two sides and any angle between the sides of one triangle are equal to the corresponding two sides and angle between the sides of the second triangle.
SSS - Side Side Side Rule
According to the SSS rule, two triangles are said to be congruent if all three sides of one triangle are proportional to the size three sides of the second triangle.
AAS - Angle Angle Side Rule
Angle-Angle-Side is abbreviated as AAS. The triangles are said to be congruent when two angles and a non-included side of one triangle match the comparable angles and sides of another triangle.
ASA - Angle Side Angle rule
According to the ASA rule, two triangles are said to be congruent if any two angles and the side contained between the angles of one triangle are proportional to the size two angles and side included in between angles of the second triangle.
RHS - Right Angle- Hypotenuse side Rule
According to the RHS rule, two right triangles are said to be equivalent if their hypotenuses and one of their sides are identical to those of another right-angled triangle.
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Answer:
Firstly
f(x)=3x-2=y then
Interchanging x and y we get
x=3y-2
x+2=3y
y=(x+2)/3
f-1(x)=(x+2)/3
f-1(13)=(13+2)/3
f-1(13)=5
Answer:
8
Step-by-step explanation:
Answer:
Step-by-step explanation:
If each blue tile has 5 sides and you know you have 3 blue tiles you can multiply 5 by 3
5 x 3 = 15 sides
Next you know the total number of sides is 30 and you just figured out that your 3 blue tiles have a total of 15 sides so you can subtract 15 from 30 to find how many sides are left
30 - 15 = 15sides
Since you know that these are not blue tiles because in the question it stated that you have 3 blue tiles. These have to be sides for red tiles.
Each red tile have 3 sides so you can divide 15 by 3
15/3 = 5
There are 5 red tiles
You are the number 5
