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djverab [1.8K]
3 years ago
13

PLSSS HELP! PLEASEEEEEEEEEEEEEEEEEEEEEE!

Mathematics
1 answer:
storchak [24]3 years ago
7 0

Answer:

81?

Step-by-step explanation

i might be wrong, if am delete this haha

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Solve for x.<br>3 - |8x-6I = 3<br><br>x= or x=
Ket [755]

Answer:

¾ = x

Step-by-step explanation:

Since 3 - 0 gives us the 3, we do this:

0 = -|8x - 6|

0 = -8x + 6 >> Distributive Property

-6 - 6

___________

-6 = -8x

__ ___

-8 -8

¾ = x

I am joyous to assist you anytime.

7 0
3 years ago
Help please, I don’t understand this
Solnce55 [7]

Answer:

r(14) = 29

Step-by-step explanation:

r(x) = 3/2x+8

r(14) = 3/2*14+8 = 21+8 = 29

6 0
3 years ago
Read 2 more answers
The area of a rectangle is 36x – 24 square units. The length is 12. Find the width.
lutik1710 [3]

Answer:

36x - 24 / 12 = 3x-2 I think

8 0
3 years ago
Jocelyn's swimming pool is 14.75 ft by 7.5 ft. find the Area of the swimming pool
Alexeev081 [22]

Answer:

Around 110.63 feet squared.

110.625 feet squared to be exact.

Step-by-step explanation:

14.75 times 7.5

6 0
3 years ago
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Which of the following functions f : {0, 1, 2, 3} ! {0, 1, . . . , 7} are one-to-one?
allsm [11]

Answer:

1. No.

f(0)=0\\1^2=1; \text{then } f(1)=1\\2^2=4\equiv 4 \text{ mod 8}; \text{then } f(2)=4\\3^2=9\equiv 1 \text{mod 8 }; \text{then } f(3)=1

Since f(1)=f(3) and 1\neq 3 then f isn't one-to-one.

2. No

f(0)=0\\1^3=1\equiv 1\text{ mod 8}; \text{then } f(1)=1\\2^3=8\equiv 0\text{ mod 8}; \text{then } f(2)=0\\3^3=27\equiv 3 \text{ mod 8}; \text{then } f(3)=3

Since f(0)=f(2) and 0\neq 2 then f isn't one-to-one.

3. No

0^3-8=-8\equiv 0\text{ mod 8}; \text{then } f(0)=0\\1^3-8=-7\equiv 1\text{ mod 8}; \text{then } f(1)=1\\2^3-8=0\equiv 0 \text{ mod 8}; \text{then } f(2)=0\\3^3-8=27-8=19\equiv 3 \text{ mod 8}; \text{then } f(3)=3\\

Since f(0)=f(2) and 0\neq 2 then f isn't one-to-one.

4. Yes

0^3+2*0=0; \text{then } f(0)=0\\1^3+2*1=3\equiv 3\text{ mod 8};  \text{then } f(1)=3\\2^3+2*2=8+4=12\equiv 4 \text{ mod 8};  \text{then } f(2)=4\\3^3+2*3=27+6=33\equiv 1\text{ mod 8};  \text{then } f(3)=1

Since f(0)\neq f(1)\neq f(2) \neq f(3), then f is one-to-one

5. Since f(1)=f(3) and 1\neq 3 then, f isn't one-to-one

3 0
3 years ago
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