Here it is given that AB || CD
< EIA = <GJB
Now
∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)
∠EIA ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)
∠IKL + ∠IKC 180° and ∠DLH + ∠JLD =180° (Linear Pair Theorem)
So
m∠IKL + m∠IKC = 180° ....(1)
But ∠IKC ≅ ∠JLD
m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)
So we have
m∠IKL + m∠JLD = 180°
∠IKL and ∠JLD are supplementary angles.
But ∠DLH and ∠JLD are supplementary angles.
∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)
Step-by-step explanation:
wait, I will look my lecture last year
Answer:
Step-by-step explanation:
The regular pentagonal pyramid has a base that is a regular pentagon and lateral faces that are equilateral triangles.
each part of the box and whisker is 25% (meaning each quartile) There are 4 quartiles so this makes 100%
So, the first being 25% and this is where the below 15 falls.
So, 25%
ALL of their points are common. If you multiply each side of the first equation by 2, you'll see that they're both the same line.
