All categories

3 years ago

What is 35-10k-115q Factorised

Mathematics

2 answers:

Elanso [62]3 years ago

8 0

Ksksijwisjsiz issiekswi jajsiwwjs

skelet666 [1.2K]3 years ago

3 0

Answer:

−

Step-by-step explanation:

-10k-115q+35

You might be interested in

X+y=-2 7x-4y=8 graph

Novay_Z [31]

Answer:

x+y=-2

7x-4y=8

Step-by-step explanation:

3 0

3 years ago

A curve is given by y=(x-a)√(x-b) for x≥b, where a and b are constants, cuts the x axis at A where x=b+1. Show that the gradient

ankoles [38]

Answer:

A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.

Solution:

We need to show that the gradient of the curve at A is 1

Here given that ,

$y=(x-a) \sqrt{(x-b)}$ --- equation 1

Also, according to question at point A (b+1,0)

So curve at point A will, put the value of x and y

$0=(b+1-a) \sqrt{(b+1-b)}$

0=b+1-c --- equation 2

According to multiple rule of Differentiation,

$y^{\prime}=u^{\prime} y+y^{\prime} u$

so, we get

${u}^{\prime}=1$

$v^{\prime}=\frac{1}{2} \sqrt{(x-b)}$

$y^{\prime}=1 \times \sqrt{(x-b)}+(x-a) \times \frac{1}{2} \sqrt{(x-b)}$

By putting value of point A and putting value of eq 2 we get

$y^{\prime}=\sqrt{(b+1-b)}+(b+1-a) \times \frac{1}{2} \sqrt{(b+1-b)}$

$y^{\prime}=\frac{d y}{d x}=1$

Hence proved that the gradient of the curve at A is 1.

7 0

3 years ago

If x^2+y^2=73 and xy=24, what is the value of (x+y)^2? And Why?

nydimaria [60]

(x+y)^2=x^2+y^2+2xy=73+2*24=73+48=121

⇒ (x+y)^2=121

7 0

3 years ago

A-b.a+b= giúp mình nhé

lilavasa [31]

Step-by-step explanation:

Did you mean:

= (a - b)(a + b)

= a.a + b.a - b.a - b.b

= a² + ba - ba - b²

= a² - b²

3 0

2 years ago

You need to solve for X

zhenek [66]

Look at the picture.

We have the proportion:

$\dfrac{x}{2}=\dfrac{305}{122}\ \ \ \ |\cdot2\\\\x=\dfrac{305}{61}\\\\x=5\ ft$

Answer: Rayan is 5 ft tall.

5 0

3 years ago