First calculate the probability of type AB, which is the remainder after subtracting types A, B and O.
P(AB) = 1-(0.34+0.12+0.5) = 1-0.96 = 0.04
Anti-b will react with types B and AB, so
P(reaction) = P(B)+P(AB) = 0.12 + 0.04 = 0.16
Answer: For this person, the probability of reaction with anti-b is 0.16
Answer:
The findings demonstrates an optimal foraging hypothesis based on maximizing caloric intake alone is probably incorrect in this case.
Explanation:
This example can also be explained by optimal foraging theory which helps in predicting the behavior of an animal which it is searching for food. Food provides energy to the animal but searching and capturing the food requires both energy and time.
So in order to maximize fitness , an animal adopts a foraging strategy which provides the most benefit which in this case is energy, for the lower cost and by maximizing the net energy gained.
Answer:
it is not better to examine 100 offspring becasue if you acidently drop some thing on it it will be dead just try 10
Explanation:
i did it on a exam
E.3/16
Vg: normal wings; vg: vestigial wings
Bt: normal wings, bt: bent wings
But to simplify, I write:
V: normal wing; v: vestigial wing
B: normal wings; b: bent wings
P: VvBb x VvBb
Gametes (both) VB, Vb, vB, vb
F1 (Punnett Square)
.....|.... VB...|...Vb...|...vB...|..vb
VB | VVBB | VVBb | VvBB | VvBb
Vb | VVBb .| VVbb | VvBb | Vvbb
vB | VvBB ..| VvBb | vvBB | vvBb
vb | VvBb ..| Vvbb. | vvBb | vvbb
Phenotypic ratio: 9/16 V-B- (normal) : 3/16 V-bb (bent) : 3/16 vvB- (vestigial) : 1/16 vvbb (vestigial-bent)
