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Verizon [17]
1 year ago
5

Single or simple sugars are called

Biology
1 answer:
notsponge [240]1 year ago
6 0

Answer:

<u>Carbohydrates.</u>

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DNA winds into chromatids before mitosis? true or false?
3241004551 [841]

Answer:

true

Explanation:

7 0
2 years ago
Mrs. Smith has blood type A. Mr. Smith has blood type B. Their first child has blood type AB. Their second child has blood type
dusya [7]

the only possibilities for the childrens genotypes are; A and AB, so the fact that the child has a blood type of O isn't possible

8 0
3 years ago
The breeding of organisms over many generations in order to achieve a desirable phenotype?
aliina [53]

Answer:

Selective breeding involves choosing parents with particular characteristics to breed together and produce offspring with more desirable characteristics. Humans have selectively bred plants and animals for thousands of years including: crop plants with better yields.

Explanation:

Hope that helps

4 0
3 years ago
Read 2 more answers
Calculate the final concentration of BSA in the problems below using the formula
Rudiy27

Answer:

A. C_2=1.5\frac{mg}{mL}

B. C_2=0.075\frac{mg}{mL}

C. C_2=0.01\frac{mg}{mL}

D. C_2=0.001\frac{mg}{mL}

Explanation:

Hello.

In this case, we must compute the final concentration in all the cases so we solve for it in the given equation:

C_2=\frac{C_1V_1}{V_2}

Thus, we proceed as follows:

A. Here, the final diluted solution includes the 300 μL of the 5 mg/ml-BSA and the 700 μL of TBS.

C_2=\frac{300\mu L*5\frac{mg}{mL} }{(300+700)\mu L}\\\\C_2=1.5\frac{mg}{mL}

B. Here, the final diluted solution includes the 50 μL of the 1.5 mg/ml-BSA, the 450 μL of water and the 500 μL of TBS.

C_2=\frac{50\mu L*1.5\frac{mg}{mL} }{(50+450+500)\mu L}\\\\C_2=0.075\frac{mg}{mL}

C. Here, the final diluted solution includes the 10 μL of the 1 mg/ml-BSA and the 990 μL of TBS.

C_2=\frac{10\mu L*1\frac{mg}{mL} }{(10+990)\mu L}\\\\C_2=0.01\frac{mg}{mL}

D. Here, the final diluted solution includes the 10 μL of the 0.1 mg/ml-BSA and the 990 μL of TBS.

C_2=\frac{10\mu L*0.1\frac{mg}{mL} }{(10+990)\mu L}\\\\C_2=0.001\frac{mg}{mL}

Best regards.

7 0
3 years ago
What if a mutation caused a change in the code so the message read GAG instead of GAC? 
How would this affect the protein produc
Anarel [89]

Answer: There will be no effect on the protein produced

Explanation:

According to the genetic code, the triplet codon GAG code for the amino acid, glutamate, while GAC code for aspartate.

Since GAG and GAC code for amino acids with similar properties (aspartate and glutamate are both acidic amino acids due to the extra carboxyl group present in their side chain), the change in nucleotide is still similar to the original, so will result in a different amino acid sequence, but will not alter the function of the protein at all. Thus, this kind of mutation is called silent mutation.

3 0
3 years ago
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