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Korolek [52]
2 years ago
5

Find the difference. (k2−7k+2)−(k2−12)

Mathematics
1 answer:
Ostrovityanka [42]2 years ago
3 0

Answer:

-7k + 14

Step-by-step explanation:

(k² - 7k + 2) - (k² - 12)

k² - 7k + 2 - k² + 12

k² - k² - 7k + 2 + 12

-7k + 14

You might be interested in
If alpha and beta are the zeroes of the polynomial f(x)= xsquare -8x +gamma such that alpha - beta = 2 find the value of gamma.
Komok [63]

Answer:

Γ = 15

Step-by-step explanation:

Given

f(x) = x² - 8x + Γ

with a = 1, b = - 8 and c = Γ , then

sum of zeros α + β = - \frac{b}{a} = - \frac{-8}{1} = 8

product of zeros = αβ = \frac{c}{a} = Γ

Given α - β = 2 , then

(α - β)² = 2²

α² - 2αβ + β² = 4 → (1)

and

(α + β)² = 8²

α² + 2αβ + β² = 64 → (2)

Add (1) and (2) term by term

2α² + 2β² = 68 ( divide through by 2 )

α² +β² = 34

Substitute α² + β² = 34 into (1)

34 - 2αβ = 4 ( subtract 34 from both sides )

- 2αβ = - 30 ( divide both sides by - 2 )

αβ = 15

Now

αβ = Γ = 15

Thus

f(x) = x² - 8x + 15

4 0
3 years ago
Hows your day going?<br> Mines Great :D
natta225 [31]

Answer:

It sucks

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Use the drop-down menus to choose steps in order to correctly solve<br> 4k−6=−2k−16−2 for k.
RoseWind [281]

From figure 1: -

From figure 2: 12

From figure 3: 6

From figure 4: -12

From figure 5: -2

Step-by-step explanation:

We need to solve the equation 4k-6=-2k-16-2 for k.

Solving:

4k-6=-2k-16-2\\4k-6=-2k-18\\4k=-2k-18+6\\4k=-2k-12\\4k+2k=-12\\6k=-12\\k=\frac{-12}{6}\\k=-2

So, the options to be selected are:

From figure 1: -

From figure 2: 12

From figure 3: 6

From figure 4: -12

From figure 5: -2

Keywords: Solving equations

Learn more about Solving equations at:

  • brainly.com/question/1616605
  • brainly.com/question/2586096
  • brainly.com/question/4046256

#learnwithBrainly

7 0
3 years ago
Evaluate 3/7r + 5/8s when r = 14 and s = 8.
Ahat [919]
In this question, plug in 14 for r and 8 for s, which will look like 3/98 + 5/64. Solve, and you will get 0.109 = 0.11.
6 0
3 years ago
Given the formula:<br><img src="https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B1%20%2B%20a%7D%7B1%20-%20a%7D%20" id="TexFormula1
shtirl [24]

12 = \frac{1+a}{1-a} => 12(1-a)= 1+ a \\=> 12 -12a = 1 + a => 12a+1 = 12-1 \\=> 13a = 11 => a= \frac{11}{13}

ok done. Thank to me :>

8 0
2 years ago
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