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2 years ago

9

(3r - 3) (r+2)help plz

1 answer:

suter [353]2 years ago

3 0

So this way we can do it. Thankyou!

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If p(x) = 3x – 2and n (x) = 2x – 5, what is the value of (n/p) (1)?

Liula [17]

Answer:

-3

Step-by-step explanation:

We want (n/p)(1). We can obtain this by finding n(1) and p(1) and then dividing as indicated:

p(1) = 3(1) - 2 = 1

n(1) = 2(1) - 5 = -3

Then (n/p) (1) = -3/1, or just -3

5 0

2 years ago

Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

$Sin \angle B =0.60$

$Cos \angle B=0.80$

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle A =\frac{BC}{BA}$

Substitute values for BC and BA

$Sin \angle A =\frac{8cm}{10cm}$

$Sin \angle A =\frac{8}{10}$

$Sin \angle A =0.80$

$Cos \angle A=\frac{AC}{BA}$

Substitute values for AC and BA

$Cos \angle A=\frac{6cm}{10cm}$

$Cos \angle A=\frac{6}{10}$

$Cos \angle A=0.60$

Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

8 0

3 years ago

Read 2 more answers

A woman went marketing for sugar for canning. In one store, sugar was 8 1/2¢ per pound and she found that she lacked 30¢ of havi

alex41 [277]

X=amount of money woman has
n=pounds of sugar
Store #1: 8.5*n=x+30
Store #2: 8*n=x-25

multiply #2 by 17/16 to make coefficient of n same as in #1

2: 8.5*n=17/16(x-25)

Subtract #2 from #1

0=x+30-17/16(x-25)
x+30-17x/16 +25*17/16
x/16=30+25*17/16
x=480+425
=905 cents
=$9.05

5 0

2 years ago

Give a helping hand please.

Studentka2010 [4]

$\frac{5}{6}$

3 0

2 years ago

What is the slope of a line that is perpendicular to the line represented by the equation 2x−5=−y?

Liula [17]

Answer:

$\frac{1}{2}$

Step-by-step explanation:

First, you need to get the equation into y = mx + b form, like this:

Add y to both sides to get y + 2x − 5= 0

Then subtract 2x to get y - 5 = -2x

Add 5 to get y = -2x + 5

Now we know the slope is -2, or -2/1.

A line that is perpendicular to it has a slope that is the first line's slope's opposite reciprocal. This means flip the fraction upside down and change the sign, which gives you positive 1/2.

3 0

3 years ago