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Dmitry [639]
3 years ago
5

Im an hour late, once again.. but i got the points remember 10am and 3pm est

Mathematics
1 answer:
Iteru [2.4K]3 years ago
3 0

Answer:

uh ok :

Step-by-step explanation:

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Which function rule describes the number of centimeters y as a function of a number of millimeters x?
ira [324]
Y= 10x
y: number of cm
x: number of mm
7 0
3 years ago
I need help on this question
olga2289 [7]

Hey there!

-1 ¼ • 9

= - (4+1)/4 • 9

= -5/4 • 9

= -(5 × 9)/4

= <u>-</u><u> </u><u>4</u><u>5/4</u>

= <u>- 11.25</u>

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8 0
2 years ago
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Find the missing term (need help)
katen-ka-za [31]

Answer:

x² - 10x + 34

Step-by-step explanation:

given the roots are x = 5 ± 3i then the factors are

(x - (5 + 3i))(x - (5 - 3i))

= (x - 5)² - 9i² ← expand (x - 5)²

= x² - 10 x + 25 + 9 → [ i² = - 1 ]

= x² - 10x + 34

the missing term is 10x



7 0
3 years ago
Which of the following is a radical equation?
MrMuchimi
It is A because it can’t be B and it can’t be C and it can’t be D so my answer is A
5 0
3 years ago
Suppose that a large mixing tank initially holds 100 gallons of water in which 50 pounds of salt have been dissolved. Another br
Serggg [28]

Answer:

dA/dt = 12 - 2A/(100 + t)

Step-by-step explanation:

The differential equation of this problem is;

dA/dt = R_in - R_out

Where;

R_in is the rate at which salt enters

R_out is the rate at which salt exits

R_in = (concentration of salt in inflow) × (input rate of brine)

We are given;

Concentration of salt in inflow = 4 lb/gal

Input rate of brine = 3 gal/min

Thus;

R_in = 4 × 3 = 12 lb/min

Due to the fact that solution is pumped out at a slower rate, thus it is accumulating at the rate of (3 - 2)gal/min = 1 gal/min

So, after t minutes, there will be (100 + t) gallons in the tank

Therefore;

R_out = (concentration of salt in outflow) × (output rate of brine)

R_out = [A(t)/(100 + t)]lb/gal × 2 gal/min

R_out = 2A(t)/(100 + t) lb/min

So, we substitute the values of R_in and R_out into the Differential equation to get;

dA/dt = 12 - 2A(t)/(100 + t)

Since we are to use A foe A(t), thus the Differential equation is now;

dA/dt = 12 - 2A/(100 + t)

5 0
2 years ago
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