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Nadya [2.5K]
3 years ago
8

One fifth of the sum of 3 and a number

Mathematics
1 answer:
Dominik [7]3 years ago
3 0

Answer:

1/5(x+3)

Step-by-step explanation:

That is, assuming the number=x

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What are the possible numbers of positive, negative, and complex zeros of f(x) = −3x4 + 5x3 − x2 + 8x + 4?
ale4655 [162]

Answer:

Either:  1 neg, 3 pos, 0 imaginary; 1 neg, 1 pos, 2 imaginary

Step-by-step explanation:

Look for the positive possibilities first.  Count the numbe of sign changes then subtract 2, if possible, as many times as you can.

There are 3 sign changes.  So the possible positive roots are either 3 or 1.

Now look for the negative possibilities.  Replace each x with a -x and then count the sign changes.  Replacing with -x's gives you this polynomial:

f(-x)=-3x^4-5x^3-x^2-8x+4

There is only one sign change here, so the possible negative roots is 1.  Start with the negative roots to find the possible combinations of positive, negative, and imaginary, since there is only 1.

-     1       1

+    3       1

i     0       2

Since this is a 4th degree, the number of roots we have has to add up to equal 4.

8 0
3 years ago
Please please help me
ohaa [14]

Answer:

b) 43 degrees

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
What is 71,781 divided by 8​
Mashutka [201]
The answer is 8,972.625
7 0
2 years ago
Describe in words the region of R3 reperesented by the equations or inequalities x2+y2+z2≤3
Vaselesa [24]

Answer:

The region represented by the equation is a full sphere of radius √3 centered in the origin of coordinates.

Step-by-step explanation:

<em>In a plane xy, the equation that represents a circle with center in the origin, of radius r is</em>

x^2+y^2=r^2

<em>in R³, or a space xyz, we can represent a sphere with its center in the origin, and of radius r, with the equation</em>

x^2+y^2+z^2=r^2

So, in this problem we have that

3=r^2

which means that the sphere has a radius of √3.

<u>Finally, our equation is an inequality</u>, and the sphere is equal to, and less than, the calculated radius.

Therefore, the sphere is "full" from the surface to its center.

8 0
3 years ago
Label the net for the figure below with its dimensions.
kogti [31]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Below is the complete solution :
- two points on earth are :
(39N,120W) and (41N,84W)
midpoint between them = <span>(<span><span>39+41/</span>2</span>N, <span><span>120+84/</span>2</span>W)
= </span>(802N, 104/2W)
= <span>(40N,52W<span>)</span></span>
6 0
2 years ago
Read 2 more answers
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