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Vinvika [58]
3 years ago
7

If you roll two four-sided dice numbered 1, 2, 3, and 4), what is the probability that the sum of the dice is 7? Enter a fractio

n, integer, or exact decimal. Do not approximate.
Mathematics
1 answer:
Anna [14]3 years ago
8 0
The probability that the sum of the dice is 7 is 1/2 because there are only three combinations that result in the sum of 7: (1,6)(2,5) and (3,4). But there are 6 possible outcomes( this is if you don’t add reverse combinations such as 1,6 and 6,1) so the probability would be 3/6 or 1/2
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3. Simplify: 13.6 - 4.1 - 3.8 + 6.7
Art [367]

Answer:

12.4 is the answer

=13.6+6.7-4.1-3.8

=20.3-7.9

=12.4

5 0
2 years ago
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What is the initial value of the equation shown? (1 point) y = −7x − 6 −13 −7 −6 −1
Liula [17]

Answer:

-6

Step-by-step explanation:

The equation is y = -7x - 6.

The initial value is found when x = 0.

y = -7(0) - 6

y = 0 - 6

y = -6

6 0
2 years ago
Ridah has a triangular garden with the sides 28m, 15m and 41m. She has planted rose and marigold plants in her garden. She used
Mama L [17]

Answer:

70m²

Step-by-step explanation:

Area of the plot=½×28×15

= 210m²

Area used by rose plants=⅔×210 =140m²

Area used by marigold=210-140

=70m²

6 0
2 years ago
a density graph for all the possible weights between 0 pounds and 100 pounds is in the shape of a rectangle. what is the height
Pavel [41]

Answer:

0.1

Step-by-step explanation:

a p e x

4 0
2 years ago
Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distribute
balu736 [363]

Answer:

The area of the shaded region is 0.9082.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value, which is the area of the shaded region, is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 100, \sigma = 15, X = 120

Area of the shaded region:

pvalue of Z

Z = \frac{X - \mu}{\sigma}

Z = \frac{120 - 100}{15}

Z = 1.33

Z = 1.33 has a pvalue of 0.9082

So

The area of the shaded region is 0.9082.

4 0
3 years ago
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