If the diameter is 12 inches, the radius is 6 inches, because the radius is half the diameter.
Given the formula
we have
When you fold the circle in half, the resulting figure has half the area.
So, you start with a circle with area 
You fold it once and you have a semicircle with area 
You fold it twice and you have a quarter circle with area 
Answer:
0.3
Step-by-step explanation:
To find p we require the cube root of 0.027, that is
p³ = 0.027, then
p = ![\sqrt[3]{0.027}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B0.027%7D)
= ![\sqrt[3]{\frac{27}{1000} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B27%7D%7B1000%7D%20%7D)
= 
= 0.3
It would be C because that is the one that make the most sense
Answer:
Kayla is correct The center is a fixed point in the middle of the sphere
Step-by-step explanation:
In mathematics we have certain habit of rules for notation of points, coordinates, segments, angles and so on.
Usually we denote points, by letters even more we denote with the first letter of the object we are denoting
Occasionally, we also denote segments as radius in a circle and in a sphere, with letters, that is r stands for radius, h stands for height, in most cases we denote point for capital letters ( in a segment)
When we denote radius, with small letter it should be placed at the center or over the segment we are traying to denote.
For points we only need to place the letter close to the to the point we want to denote.
Therefore Kayla is correct when says that c stand for " the center of the sphere"
<h3>
Answer: Choice A) 212 square meters</h3>
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Explanation:
14.10 has four sig figs. The 0 at the end is significant. This measurement is accurate to the hundredths place. If the author wrote 14.1, then it would be accurate to the tenths place with three sig figs.
15.0 has three sig figs. The 0 is significant. If they wrote 15 or 15. then we'd be dealing with 2 sig figs instead; however they placed the 0 there to tell the reader "this measurement is accurate to the tenths place"
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Multiply the values given
14.10*15.0 = 211.5
Round that to three sig figs. We pick the smaller sig fig count to round to since we cannot be certain it is accurate to four sig figs. In a sense, we pick the weakest link and use that to determine rounding when it comes to multiplication and division.
This means 211.5 rounds to 212
