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3 years ago

Suppose y varies inversely with x, and y=39 when x=1/3.what is the value of y when x=26

Mathematics

2 answers:

ivanzaharov [21]3 years ago

7 0

Answer:

y = $\frac{1}{2}$

Step-by-step explanation:

Given y varies inversely with x then the equation relating them is

y = $\frac{k}{x}$ ← k is the constant of variation

To find k use the condition y = 39 when x = $\frac{1}{3}$ , then

39 = $\frac{k}{\frac{1}{3} }$ ( multiply both sides by $\frac{1}{3}$ )

$\frac{1}{3}$ × 39 = k

13 = k

y = $\frac{13}{x}$ ← equation of variation

When x = 26 , then

y = $\frac{13}{26}$ = $\frac{1}{2}$

vagabundo [1.1K]3 years ago

6 0

Answer:

y = 1/2

Step-by-step explanation:

Varies inversely

xy = k

------------------------

Find the constant of variation

y = 39 when x = 1/3

k = 1/3 * 39

k = 13

-----------------------

what is the value of y when x=26

26y = 13

y = 13/26

y = 1/2

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