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tekilochka [14]
3 years ago
5

Suppose y varies inversely with x, and y=39 when x=1/3.what is the value of y when x=26

Mathematics
2 answers:
ivanzaharov [21]3 years ago
7 0

Answer:

y = \frac{1}{2}

Step-by-step explanation:

Given y varies inversely with x then the equation relating them is

y = \frac{k}{x} ← k is the constant of variation

To find k use the condition y = 39 when x = \frac{1}{3} , then

39 = \frac{k}{\frac{1}{3} } ( multiply both sides by \frac{1}{3} )

\frac{1}{3} × 39 = k

13 = k

y = \frac{13}{x} ← equation of variation

When x = 26 , then

y = \frac{13}{26} = \frac{1}{2}

vagabundo [1.1K]3 years ago
6 0

Answer:

y = 1/2

Step-by-step explanation:

Varies inversely

xy = k

------------------------

Find the constant of variation

y = 39 when x = 1/3

k = 1/3 * 39

k = 13

-----------------------

what is the value of y when x=26

26y = 13

y = 13/26

y = 1/2

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