A quadratic function is a function of the form
. The
vertex,
of a quadratic function is determined by the formula:
and
; where
is the
x-coordinate of the vertex and
is the
y-coordinate of the vertex. The value of
determines if the <span>
parabola opens upward or downward; if</span>
is positive, the parabola<span> opens upward and the vertex is the
minimum value, but if </span>
is negative <span>the graph opens downward and the vertex is the
maximum value. Since the quadratic function only has one vertex, it </span><span>could not contain both a minimum vertex and a maximum vertex at the same time.</span>
X=3 is a vertical line . The question is "Is this line a vertical asymptotefor the function f(x)?". Vertical asymptote is vertical line near which the function grows without bound.
The function f(x)=5x-15/x-3 is not asymptotic to the line x=3, because for x=3 f(x)=5*3-15/3-3=0/0=0 . So, there is a value for x=3 and the function f(x) does not grow near x=3 without bound.
Answer:
<em>x = 6 and y = 25 → (6, 25)</em>
Step-by-step explanation:
Substitute y = 4x + 1 to the equation 2x + y = 37:
2x + (4x + 1) = 37
(2x + 4x) + 1 = 37 <em>subtract 1 from both sides</em>
6x = 36 <em>divide both sides by 6</em>
x = 6
Pyt the value of x to the first equation:
y = 4(6) + 1
y = 24 + 1
y = 25
We need to find mean of given integers.
We have -16,39,-10,-16,12,31.
In order to find mean, we need to add all the given inetgers.
Therefore, putting plus sign in between integers.
-16+ 39+ (-10)+(-16)+12+31 .
We will add all positive number 39+12+31 = 82
We will add all negative numbers by negative numbers, -16-10-16 = -42.
Therefore, -16+ 39+ (-10)+(-16)+12+31 = 82 - 42 = 40.
We have given total 6 integers.
So, in order to find the mean, we need to apply following formula
Mean = 
We get,
Mean = 40/6 = 6.66666......
We can round it to 6.67.
Therefore, mean of the given integers = 6.67 (approximately) .
Answer:
Rv and EA
Step-by-step explanation:
Because ik
