Answer:
400 square meters
Step-by-step explanation:
We can first solve this problem with each unit representing 1 centimeter, and then scale up at the very end. The shape that we have a parallelogram. The base is 8 cm, and the height is 2 cm. The formula for the area of a parallelogram is just 
, so the area of the parallelogram is 16 square centimeters. However, now we scale up. Since each centimeter correlates to 5 meters, each little box will correlate to 25 square meters. Therefore, 
square meters is our answer
Answer:
67 1/2 is a mixed number
Step-by-step explanation:
The volume of a prism, is the area of the cross section X the length:
In this case it is base × height × length:
6 × 4.5 × 2.5 = 67.5cm^3
= 67 1 / 2 as a mixed number
Answer:
25%- 1875 Votes
<em>7500 x 0.55 = 4125 (</em><em>first candite valid votes</em><em>)</em>
<em>7500 x 0.20 = 1500 (</em><em>invalid</em><em>)</em>
<em>first candite valid votes</em><em> </em><em>(</em><em>55</em><em>) + invalid votes (</em><em>20</em><em>) = 75% of total votes </em>
<em>first candite valid votes</em><em> </em><em>(</em><em>4125</em><em>) + invalid votes (</em><em>1500 </em><em>) = 5625 of total votes </em>
<em />
<em>100 (</em><em>total</em><em> </em><em>percent of votes</em><em>) - 75 (</em><em>total percent of votes</em><em>) = 25% Votes Left</em>
<em>7500 (</em><em>total</em><em> </em><em>number of votes</em><em>) - 5625 (</em><em>total number of votes</em><em>) = 1875 Votes Left</em>
<em>7500 x 0.25 = 1875 (</em><em>valid votes for the other candite</em><em>)</em>
<em> </em>
1a) f(x) = I x+2 I. This is a piece-wise graph ( V form)
x = 0 →f(x) =2 (intercept y-axis)
x = -2→f(x) = 0 (intercept x-axis)
x = -3→f(x) = 1 (don't forget this is in absolute numbers)
x = -4→f(x) = 2 (don't forget this is in absolute numbers)
Now you can graph the V graph
1b) Translation: x to shift (-3) units and y remains the same, then
f(x-3) = I x - 3 + 2 I = I x-1 I
the V graph will shift one unit to the right, keeping the same y. Proof:
f(x) = I x-1 I . Intercept x-axis when I x-1 I = 0, so x= 1
