Answer:
3yz² - 3z² - 5y + 7
Step-by-step explanation:
Sum of two polynomials = –yz² - 3z² – 4y + 4
One of the polynomial = y - 4yz²- 3
Find the other polynomial
The other polynomial = sum of the polynomials - one of the polynomial
= –yz² - 3z² – 4y + 4 - (y - 4yz² - 3)
= –yz² - 3z² – 4y + 4 - y + 4yz² + 3
= -yz² + 4yz² - 3z² - 4y - y + 4 + 3
= 3yz² - 3z² - 5y + 7
A. 0 -2yz?
B. – 4y + 7 01 - 2yz
C. – 3y + 1 0 -5yz² + 3z² – 3y + 1 D. 3yz² - 3z² – 5y + 7
Answer:
-24
Step-by-step explanation:
plz mark brainlyest
Answer:
I guess option c is the answer
When both increase, the slope is positive (+)/(+)=(+)
The slope of the function is given by its derivative. You want to find the values of x such that the derivative is between -1 and 1.
... f'(x) = 0.4x +5
... -1 < 0.4x +5 < 1 . . . . . your requirement for slope
... -6 < 0.4x < -4 . . . . . . subtract 5
... -15 < x < -10 . . . . . . . multiply by 2.5
Any value of x that is between -15 and -10 will be one where the tangent line has a slope between -1 and 1.
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The graph shows tangent lines with slopes of -1 and +1. You can see that the slope of the graph of f(x) is between those values when x is between the tangent points.