Answer:
we have centre of circle as (30,40) and radius = 1
Step-by-step explanation:
Given that a car is moving on a circle on a plane.
At time t (seconds),
and
when we square and add both the equations we get
(since sin square + cos square = 1 always)
i.e. we have centre of circle as (30,40) and radius = 1
Answer:
Step-by-step explanation:
we know that
The area of the shaded region is equal to the area of triangle plus the area of semicircle
so
we have
Find the height of the right triangle applying the Pythagorean Theorem
The radius of the semicircle is half the height of triangle
substitute in the formula
Answer:
Step-by-step explanation:
I'm assuming you meant to type in
because you can only have removable discontinuities where there is a rational (fraction) function. Begin by factoring both the numerator and denominator to
and cancelling out like terms would have us eliminating the (x + 3). That is where there is a removable discontinuity. It leaves a hole. The other discontinuity, (x + 1) doesn't cancel out so it is a non-removable discontuinity, which is a vertical asymptote.
The removable discontinuity is at -3. There is no y value at x = -3 (remember there's only a hole here), because -3 causes the denominator to go to 0 and we all know that having a 0 in the denominator of a fraction is a big no-no!!!