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juin [17]
3 years ago
9

The graphs below have the same shape. what is the equation of the graph of g(x)​

Mathematics
1 answer:
anygoal [31]3 years ago
7 0

Answer:

D

Step-by-step explanation:

Proablas always have x squared. They are never in parentheses. The plus or minus sign determine who way it's facing.

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An experimenter used the following design for studying five variables in eight runs in four blocks of size 2. (a) By reordering
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Answer:

A design in which all levels of each independent variable are combined with all levels of the other independent variables. A factorial design allows investigation of the separate main effects and interactions of two or more independent variables.

Step-by-step explanation:

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Read 2 more answers
The cost to produce a product is modeled by the function f(x) = 5x2 − 70x 258, where x is the number of products produced. compl
ad-work [718]

The minimum cost to produce the product is $7.

What are functions?

  • A function from a set X to a set Y allocates exactly one element of Y to each element of X.

To determine the minimum cost:

We have to determine the minimum cost of producing this product.

Since f(x) = 5x^{2} -70x+258.

Now, consider the equation 5x^{2} -70x+258= 0.

Dividing the above equation by 5, we get

x^{2} -70x/5+258/5=0\\x^{2} -14x+258/5=0

Now, considering the coefficient of 'x', dividing it by '2' and then adding and subtracting the square of the number which we got after dividing.

Since the coefficient of 'x' is 14, and half of 14 is '7'.

So, adding and subtracting from the above equation.

x^{2} -14x+(7)^{2} -(7)^{2}+258/5=0\\x^{2} -14x+49 -49+258/5=0\\(x-7)^{2} -49+258/5=0\\(x-7)^{2} +258-245/5=0\\(x-7)^{2} +13/5=0\\5(x-7)^{2} +13=0

Now, we have to determine the minimum cost to produce the product.

Since f(x) = 5x^{2} -70x+258.

f'(x) = 10x-70

Now, let f'(x)=0

10x-70=0\\10x=70

Therefore, x=7

Now, consider which is greater than 0.

Therefore, x= 7 is the minimum cost.

Know more about functions here:

brainly.com/question/25638609

#SPJ4

5 0
2 years ago
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