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Natalija [7]
3 years ago
15

Solve the equation

TexFormula1" title="16 {}^{2x - 3} = 8 {}^{4x} " alt="16 {}^{2x - 3} = 8 {}^{4x} " align="absmiddle" class="latex-formula">
​

Mathematics
1 answer:
kompoz [17]3 years ago
3 0

Answer:

<h2>n = -3</h2>

Step-by-step explanation:

16=2^4\\\\8=2^3\\\\16^{2n-3}=8^{4n}\\\\(2^4)^{2n-3}=(2^3)^{4n}\qquad\txt{use}\ (a^n)^m=a^{nm}\\\\2^{(4)(2n-3)}=2^{(3)(4n)}\iff4(2n-3)=12n\qquad\text{use the distributive property}\\\\(4)(2n)+(4)(-3)=12n\\\\8n-12=12n\qquad\text{subtract}\ 8n\ \text{from both sides}\\\\-12=4n\qquad\text{divide both sides by 4}\\\\\dfrac{-12}{4}=\dfrac{4n}{4}\\\\-3=n\to n=-3

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<h3>How to determine angle <XYZ?</h3>

By critically observing the geometric shapes shown in the image attached below, we can deduce that they obey the theorem of intersecting secants.

<h3>What is the theorem of intersecting secants?</h3>

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