4x-7=37
4x=37+7
4x=44
4x/4=44/4
X=11
The law of an object moving with constant acceleration is
Where 
is space, 
is time, 
is the initial position, 
is the initial velocity and 
is the acceleration.
In this case, if we choose a reference grid with the vertical axis pointing upwards, the acceleration of gravity will point downwards (and thus be negative). The initial position is zero, because the rocket is on the ground, and the initial velocity is 100 (positive because pointing upwards).
So, its law is
(I changed for 
since the rocket is moving vertically, so its position is actually its height. Also, g is the acceleration due to gravity).
The rocket hits the ground if its height is zero, so if we set 
we have
Solving for t, we have either t=0, or
The solution t=0 means that at the beginning the rocket is on the ground. So, we're interested in the other solution. Considering that g is about 32.2 feet/s^2, we have
The answer is= a(15) and b(135) and c (135)
Answer:
Tara's current expression finds how much the school will be keeping. 50 x 2/5 (also written as 50 x 0.4) totals out as 20. $20 is 2/5 of $50. The expression that Tara SHOULD have written to find how much goes to the candle company would be 50 x 3/5 (also written as 50 x 0.6), as this adds up to 30. $30 is 3/5 of $50.
Step-by-step explanation:
50/5 = 10 which means that 1/5 of 50 = 10.
2/5 of 50 ($20) is kept by the school. This is what Tara's expression finds. This means that $30 is sent to the candle company, and can be found with the expression 50 x 3/5.
The decimals are created by dividing the numerator of the fraction by the denominator (I find it easier to do math with decimals).
Answer:
C is the equation that is perpendicular and goes through the given point.
Step-by-step explanation:
In order to find this, we first need to find an equation with the appropriate slope. Perpendicular lines have opposite and reciprocal slopes. Since the slope of the original line is 1, we need a line with -1 slope. C and D are the only such answers that have this slope.
Next we look for it to fit into the following point slope equation.
y - y1 =m(x - x1)
We use the point (2, 5) as (x1, y1). So we can plug those in the spots that we see above as well as the slope at m.
y - y1 =m(x - x1)
y - 5 = -(x - 2)
