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erastova [34]
3 years ago
5

Factor out the coefficient of the variable 2.2x+4.4

Mathematics
1 answer:
OleMash [197]3 years ago
7 0
The coefficients are the numbers in front of x or the 4.4 in the equation. So you can just divide the numbers.

2.2x + 4.4                Divide to 2.2
x + 2
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The coordinates of the vertices of a polygon are (-2, 1). (-3, 3), (-1, 5), (2, 4), and (2, 1). What is the perimeter of the pol
kobusy [5.1K]

Answer:

15.2\ units

Step-by-step explanation:

step 1

Plot the vertices of the polygon to better understand the problem

we have

A(-2, 1). B(-3, 3), C(-1, 5), D(2, 4),E(2, 1)

using a graphing tool

The polygon is a pentagon (the number of sides is 5)

see the attached figure

The perimeter is equal to

P=AB+BC+CD+DE+AE

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 2

<em>Find the distance AB</em>

A(-2, 1). B(-3, 3)

substitute in the formula

d=\sqrt{(3-1)^{2}+(-3+2)^{2}}

d=\sqrt{(2)^{2}+(-1)^{2}}

d_A_B=\sqrt{5}=2.24\ units

step 3

<em>Find the distance BC</em>

B(-3, 3), C(-1, 5)

substitute in the formula

d=\sqrt{(5-3)^{2}+(-1+3)^{2}}

d=\sqrt{(2)^{2}+(2)^{2}}

d_B_C=\sqrt{8}=2.83\ units

step 4

<em>Find the distance CD</em>

C(-1, 5), D(2, 4)

substitute in the formula

d=\sqrt{(4-5)^{2}+(2+1)^{2}}

d=\sqrt{(-1)^{2}+(3)^{2}}

d_C_D=\sqrt{10}=3.16\ units

step 5

<em>Find the distance DE</em>

D(2, 4),E(2, 1)

substitute in the formula

d=\sqrt{(1-4)^{2}+(2-2)^{2}}

d=\sqrt{(-3)^{2}+(0)^{2}}

d_D_E=\sqrt{9}\ units

d_D_E=3\ units

step 6

<em>Find the distance AE</em>

A(-2, 1).E(2, 1)

substitute in the formula

d=\sqrt{(1-1)^{2}+(2+2)^{2}}

d=\sqrt{(0)^{2}+(4)^{2}}

d_A_E=\sqrt{16}\ units

d_A_E=4\ units

step 7

Find the perimeter

P=AB+BC+CD+DE+AE

substitute the values

P=2.24+2.83+3.16+3+4=15.23\ units

Round to the nearest tenth of a unit

P=15.2\ units

6 0
3 years ago
The cost of 18 notebooks at store j is $22.50. The notebooks at store j are all same price. The cost of notebooks at store k is
anzhelika [568]

Answer:

Where is the graph?

Step-by-step explanation:

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3 years ago
Read 2 more answers
Help me plz and thx :)
ikadub [295]

Answer:

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A group of 18 people ordered soup and sandwiches for lunch. Each person in the group had either one soup or one sandwich. The sa
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Check it out .....


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Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.
tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: \frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3} square units

(22)

Similar to (21)

Area = 216\sqrt{3} square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

altitude=\frac{\sqrt{3}}{2}*side

side = \frac{36}{\sqrt{3}}

Hence, area of the hexagon will be: 648\sqrt{3} square units

(24)

Given is the inradius of an equilateral triangle.

Inradius = \frac{\sqrt{3}}{6}*side

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

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Area of equilateral triangle = \frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3} square units

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3 years ago
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