The data set shows the ages of everyone in a dance class.
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The <em>expected number of mortgages</em> approved per week and the standard deviation of the distribution are 2.019 and 0.024 respectively.
<u>The expected number of mortgages approved per week</u> :
- <em>Mean = (Σfx ÷ Σf)</em>
Expected Number approved = 210 ÷ 104 = 2.019
Hence, it is expected that 2.019 mortageahes would be approved per week.
<u>The standard deviation</u> :
- <em>Variance = [Σ(Xi - x)² ÷ Σf] </em>
- <em>Standard deviation = √Variance</em>
Variance = (59.5414 ÷ 104) = 0.0005698
Standard deviation = √0.0005698
Standard deviation = 0.024
Therefore, the expected value and standard deviation are 2.019 and 0.024 respectively.
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Answer:
See Annex In blue feasible region ( using Geogebra)
Step-by-step explanation:
Table 1.-
Assembling hours finishing hours
Product (tables) x 8 2
Product ( chairs) y 2 1
Availability 400 120
Constrains:
1.-Availability of assembling hours 400
8*x + 2* y ≤ 400
2.-Availability of Finishing hours
2*x + 1*y ≤ 120
3.-General constraints
x ≥ 0 y ≥ 0 integers
