Question

Mr.Lee is shopping for a new electric water heater. Brand A costs $586 and uses 444 kilowatt-hours per month. Brand B costs $639 and uses 377 kilowatt-hours per month. If electricity costs $0.17 per kilowatt-hour, how much would Mr.Young save on electricity per month by buying brand B?

Answer 1

Answer:

mr.young would save 11.39 per month on buying brand b

Step-by-step explanation:

0.17×444=75.48

0.17×377=64.09

75.48-64.09=11.39