Answer: The Median: 78, The First Quartile: 63, and The Third Quartile: 99
Step-by-step explanation: Ok, so let's put the data set from least to greatest....
(63, 63, 76,) (77, 79,) (84, 99, 99)
First Quartile Third Quartile
First, let's find the median, since you made a little mistake...
77 + 79 = 156
156 ÷ 2 = 78
The median is 78!
Now, let's determine the first quartile and the third quartile.
For the the first quartile/third quartile it'll be the middle number, if it's even we'll do the same extra step just like we'll do for the median. In this case it's not even therefore...
First Quartile: 63
Third Quartile: 99
I hope this helps!
Answer:
The third one!
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
- 
(x + 3) > x - 3 ( multiply both sides by 2 to clear the fraction )
- (x + 3) > 2x - 6 ← distribute parenthesis on left side by - 1
- x - 3 > 2x - 6 ( subtract 2x from both sides )
- 3x - 3 > - 6 ( add 3 to both sides )
- 3x > - 3
divide both sides by - 3, reversing the symbol as a result of dividing by a negative quantity
x < 1
Answer:
360
Step-by-step explanation:
You will need 2 * 2 * 2 for the smallest number to be divisible by 8 with all the others.
You will need 3 * 3 for the smallest number to be divisible by 9 with all the others.
Finally you will need 1 five
The smallest number divisible by all of these is 2*2*2*3*3*5 = 360
- 360/2 = 180 works
- 360/3 = 120 works
- 360/5 = 72 works
- 360/6 = 60 works
- 360/8 = 45 works
- 360/9 = 40 works.
There is no smaller number below 360 which will work.
Answer: 1200 minus 700=500 divided by 5=100
Step-by-step explanation: I got it right on a test
