<span>Let A be the center of a circle and two angles at the adjacent center AOB and BOC. Knowing the measure of the angle AOB = 120 and the measure BOC = 150, find the measures of the angles of the ABC triangle.
</span>solution
Given the above information;
AC=AB, therefore ABC is an isosceles triangle.
therefore, BAO=ABO=(180-120)/2=30
OAC=OCA=(180-90)/2=45
OBC=BCO=(180-150)/2=15
THUS;
BAC=BAO+OAC=45+30=75
ABC=OBA+CBO=15+30=45
ACB=ACO+BCO=15+45=60
I would first cut off the ends that make a trapezoid and then find the area of the trapezoids and the area of the rectangles.
A trap = (1/2) * h *(b1 + b2)
A rect = L * W
A trap = (1/2) 4 * (6 + 14)
A = (1/2) * 4 * 20
A = 40 (there are 2 trapezoids) 40 * 2 = 80 yds^2
A rect = L * W
A = 12 * 4
A = 48 (there are 2 rectangles) 48 * 2 = 96 yds^2
80 + 96 = 176 yds^2
Answer:
a
Step-by-step explanation:
Answer:
C) 22 pi
Step-by-step explanation:
Here the diameter of the circle = 24.
Therefore, radius of the circle = 24/2 = 12 ft
Here we have to use the formula to find the arc length.
Arc length = (central angle / 360) * 2*pi*r
Central angle ABC = 360 - 30 = 330 degrees and radius (r) = 12
Now plug in these values in the formula, we get
Arc length ABC = (330/360) *2*pi*12
Now we have to simplify it.
= 11/12 *2 *pi*12
= 11*2*pi
Arc length of ABC = 22pi
Therefore, the answer is C) 22 pi
Hope you will understand the concept.
Thank you.
Answer:
0
Step-by-step explanation:
What ever times 0 always is 0, take 100 × 0 it will make it Into 0. If you need help use a calculator, hope this helps
