Write an equation of a line that is perpendicular to the line 2x-3y+15=0
1 answer:
Answer:
Step-by-step explanation:
The equation of the given straight line is 2x - 3y + 15 = 0.
Now, we can express the equation as 3y = 2x + 15
⇒ ..........(1)
The equation is in slope-intercept form and the slope is =
Therefore, the equation of a straight line which is perpendicular to (1) is
{Where c is any constant}
{Since, the product of slopes of two perpendicular straight lines is -1}
Now, putting c = 1, we get the equation as . (Answer)
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