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3 years ago

Write an equation of a line that is perpendicular to the line 2x-3y+15=0

Mathematics

1 answer:

loris [4]3 years ago

4 0

Answer:

$y =- \frac{3}{2} x+1$

Step-by-step explanation:

The equation of the given straight line is 2x - 3y + 15 = 0.

Now, we can express the equation as 3y = 2x + 15

⇒ $y = \frac{2}{3} x+ 5$ ..........(1)

The equation is in slope-intercept form and the slope is = $\frac{2}{3}$

Therefore, the equation of a straight line which is perpendicular to (1) is

$y = -\frac{3}{2} x+c$ {Where c is any constant}

{Since, the product of slopes of two perpendicular straight lines is -1}

Now, putting c = 1, we get the equation as $y =- \frac{3}{2} x+1$ . (Answer)

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3 years ago

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3 years ago

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2 years ago

if an elephant were scaled up to triple its size while retaining its present proportions, its strength-to-weight ratio would be

andre [41]

Answer:

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3 years ago

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luda_lava [24]

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