Write an equation of a line that is perpendicular to the line 2x-3y+15=0
1 answer:
Answer:
Step-by-step explanation:
The equation of the given straight line is 2x - 3y + 15 = 0.
Now, we can express the equation as 3y = 2x + 15
⇒ ..........(1)
The equation is in slope-intercept form and the slope is =
Therefore, the equation of a straight line which is perpendicular to (1) is
{Where c is any constant}
{Since, the product of slopes of two perpendicular straight lines is -1}
Now, putting c = 1, we get the equation as . (Answer)
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Answer:
Step-by-step explanation:
An obtuse angle in the triangle is opposite to the greatest side. The greatest side in the triangle with sides lengths 2, 2 and 3 is side with length 3. By the cosine rule,
Hello.
There are really 2 ways to think about the given problem.
First, we can use the slope formula:
Slope = undefined
The second way is to just take a look at the points.
You should notice that the x-coordinates are the same.'
If the x-coordinates are the same, then the slope is
I hope it helps.
Have a nice day.
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Answer:
f(x) = sin(0.62832(x +1))
Step-by-step explanation:
The period of the function is the difference between x=4 and x=-6, which is 10 units. Then the horizontal scaling needs to be such that when x changes by 10, the argument of the sine function changes by 2π. That scaling will make it ...
f(x) = sin(2π(x/10)) = sin(πx/5)
The upward zero-crossing is seen to be at -1, so this function has been shifted left 1 unit. This requires we replace x with x+1:
f(x) = sin(π/5(x +1))
If we use the given numerical value for pi, this becomes ...
f(x) = sin(0.62832(x +1))
